NC EOG/EOC NC Math 3 Statistics and Probability. Practice it free.

EOC NC Math 3 domain (8-12% of the test, Table 1). Understand and evaluate random processes underlying statistical experiments, and make inferences and justify conclusions from sample surveys, experiments, and observational studies (S-IC). This NC Math 3 reporting domain maps to 1 practice skill and 8 representative questions from the playable bank.

NC Math 3S1 mapped skills
What the test measures

Statistics and Probability skills

  1. Understand statistics as a process for making inferences about population parameters based on a random sample (NC.M3.S-IC.1)

  2. Recognize the purposes of and differences among sample surveys, experiments, and observational studies (NC.M3.S-IC.3)

  3. Use data from a sample survey or experiment to estimate and compare parameters and evaluate reports (NC.M3.S-IC.4, NC.M3.S-IC.5, NC.M3.S-IC.6)

Standards basis

North Carolina Standard Course of Study (NCSCOS) — North Carolina

How the NC EOG/EOC reports it

North Carolina’s math assessments are state-developed EOG/EOC tests aligned to the North Carolina Standard Course of Study (NCSCOS) for Mathematics, adopted June 2016, rather than a shared multistate framework. The EOG Grades 3-8 Mathematics Test Specifications and the EOC NC Math 1 and NC Math 3 Test Specifications publish, in Table 1/Table 2, the range of total items by domain (the official domain weight distributions). The NCSCOS K-8 domains carry CCSS domain codes (NC.3.OA, NC.8.F, …) and are CCSS-derived; NC Math 1 and NC Math 3 are integrated high-school EOC courses whose standards carry NC.M1/NC.M3 conceptual-category codes (Number and Quantity, Algebra, Functions, Geometry, Statistics and Probability).

Blueprint & weighting

Published per-domain weight ranges come from the NC DPI EOG/EOC Mathematics Test Specifications (April 2026), Table 1/Table 2 (range of total items by domain). EOG grades 3-5 (Table 1): Operations and Algebraic Thinking 32-36% (g3) / 14-18% (g4) / 9-13% (g5); Number and Operations in Base Ten 9-13% / 25-29% / 25-29%; Number and Operations – Fractions 28-32% / 30-34% / 39-43%; Measurement and Data, Geometry 23-27% / 23-27% / 19-23%. EOG grades 6-8 (Table 2): Ratios and Proportional Relationships 24-28% (g6) / 24-28% (g7) / — (g8); The Number System 20-24% / 8-12% / —; Expressions and Equations 22-26% / 20-24% / —; The Number System, Expressions and Equations (combined) — / — / 24-28%; Functions — / — / 28-32%; Geometry 12-16% / 16-20% / 24-28%; Statistics and Probability 12-16% / 22-26% / 16-20%. EOC (Table 1): NC Math 1 — Number and Quantity and Algebra 36-40%, Functions 32-36%, Geometry 8-12%, Statistics and Probability 18-20%; NC Math 3 — Number and Quantity and Algebra 32-36%, Functions 32-36%, Geometry 20-24%, Statistics and Probability 8-12%.

Practice by skill

Topics mapped to this domain

Try it now

8 free questions · 0/0 correct

Practice playmedium

The mass of a chemical sample is modeled by m(x)=480(0.92)xm(x)=480(0.92)^x, where xx is the number of days after an initial measurement. According to the model, by what percent does the mass of the sample decrease each day?

The factor 0.920.92 means that each day the mass is 92%92\% of the previous day's mass, so the daily decrease is 100%92%=8%100\% - 92\% = 8\%.

Practice playmedium

An online store's weekly visitors are modeled by v(w)=1,250(1.08)wv(w)=1{,}250(1.08)^w, where ww is the number of weeks after a launch campaign begins. According to the model, how many visitors does the store have 22 weeks after the campaign begins?

Substitute w=2w=2: v(2)=1,250(1.08)2=1,250(1.1664)=1,458v(2)=1{,}250(1.08)^2=1{,}250(1.1664)=1{,}458.

Practice playmedium

A cold front is expected to reduce a reservoir's algae volume by 34\frac{3}{4} of its previous amount each week. The volume is 640640 cubic meters at the start of week 00. Which equation models the algae volume A(w)A(w), in cubic meters, after ww weeks?

A reduction of 34\frac{3}{4} of the previous volume leaves a remaining factor of 14\frac{1}{4} each week. Starting from 640640, the volume after ww weeks is A(w)=640(14)wA(w)=640\left(\frac{1}{4}\right)^w.

Practice playeasy

A librarian checked 4040 books selected at random from a collection of 800800 books. She found that 1414 of the books in the sample were fiction. Based on the sample, which of the following is the best estimate of the number of fiction books in the collection?

The sample proportion is 1440=720\dfrac{14}{40} = \dfrac{7}{20}. The best estimate for the collection is 720×800=280\dfrac{7}{20} \times 800 = 280 books.

Practice playeasy

A ball is tossed upward from a platform. The equation h=4.9t2+14t+21h = -4.9t^2 + 14t + 21 represents this situation, where hh is the height of the ball above the ground, in meters, tt seconds after it is tossed. According to the equation, what is the height, in meters, of the platform from which the ball was tossed?

At the moment of release, t=0t = 0. Substituting gives h=4.9(0)2+14(0)+21=21h = -4.9(0)^2 + 14(0) + 21 = 21 meters.

Practice playeasy

A stone is thrown upward from the edge of a cliff overlooking a valley. The equation s=5t2+11t+16s = -5t^2 + 11t + 16 models the stone's height ss, in meters, above the valley floor tt seconds after it is thrown. According to the equation, what is the height, in meters, of the cliff edge above the valley floor?

When the stone is thrown from the cliff edge, t=0t = 0. Then s=5(0)2+11(0)+16=16s = -5(0)^2 + 11(0) + 16 = 16 meters above the valley floor.

Practice playeasy

A football is kicked from a stadium deck. The equation d=16t2+48t+64d = -16t^2 + 48t + 64 represents this situation, where dd is the height of the football above the field, in feet, tt seconds after it is kicked. According to the equation, what is the height, in feet, of the deck from which the football was kicked?

When the kick occurs, t=0t = 0. Substituting gives d=16(0)2+48(0)+64=64d = -16(0)^2 + 48(0) + 64 = 64 feet.

Practice playmedium

A grocer surveyed 2525 customers selected at random and found that 1515 of them purchased at least one organic item. Based on the survey, which of the following is the best estimate of the number of customers out of 500500 who would purchase at least one organic item?

The sample proportion is 1525=35\dfrac{15}{25} = \dfrac{3}{5}. The best estimate for 500500 customers is 35×500=300\dfrac{3}{5} \times 500 = 300 customers.

Keep practicing

Turn statistics and probability into game time.

The NC EOG/EOC placement starts with this test's real coverage map and finds the right difficulty.