NDSA Grade 7 Statistics and Probability. Practice it free.

Uses random sampling and probability models to analyze variability and make inferences. This Grade 7 reporting domain maps to 7 practice skills and 8 representative questions from the playable bank.

Grade 77.SP7 mapped skills
What the test measures

Statistics and Probability skills

  1. Use random sampling to draw inferences about a population.

  2. Draw informal comparative inferences about two populations.

  3. Investigate chance processes and develop, use, and evaluate probability models.

Standards basis

North Dakota State Content Standards for Mathematics — North Dakota

How the NDSA reports it

North Dakota administered its own state assessment program (the NDSA, a Cambium computer-adaptive test in grades 3-8 and 10; replaced by ND A+ beginning spring 2025). An official NDSA mathematics public-facing CAT blueprint (Cambium/NDDPI, Oct 2020) does exist and lists per-grade reporting categories with percentage ranges, but its full per-grade table could not be retrieved character-for-character from a citable primary source for transcription here (the Cambium content CDN blocks programmatic access). The NDSA reporting categories are the CCSS-M grade-level domains: the assessment was built on North Dakota's 2017 math standards, which are verbatim CCSS-M organized by grade-level domains. The coverage map below uses North Dakota's 2023-standards-style domain/standard codes (e.g. 3.AR.OA) but the skill content is CCSS-M.

Blueprint & weighting

An official NDSA mathematics CAT blueprint (Cambium/NDDPI public-facing CAT version, Oct 2020) publishes per-grade reporting-category percentage ranges (e.g. grade 3 Operations and Algebraic Thinking ~31-34%, Number and Operations in Base Ten ~22-24%; grade 6 groups Ratios & Proportional Relationships and The Number System ~28-34% and Expressions and Equations ~25-29%). The complete per-grade table could not be retrieved verbatim from a citable primary source (the Cambium content CDN returns HTTP 403 to programmatic fetches), so domain weights in the mapping are left null rather than transcribing partial/uncertain figures or splitting blueprint percentages across the grade-6+ domain groupings.

Try it now

8 free questions · 0/0 correct

Practice playeasy

For two independent events, the probability of flipping two heads in a row: P(A)=12P(A)=\tfrac{1}{2}, P(B)=12P(B)=\tfrac{1}{2}. Find P(A and B)P(A \text{ and } B) as a simplified fraction.

Multiply: P(A and B)=12×12=14P(A \text{ and } B) = \tfrac{1}{2} \times \tfrac{1}{2} = \tfrac{1}{4}.

Practice playeasy

A bowl contains 44 lemons and 99 limes. One piece of fruit is chosen at random. What is the probability that the fruit is a lime?

There are 4+9=134 + 9 = 13 pieces of fruit and 99 are limes, so P(lime)=913P(\text{lime}) = \dfrac{9}{13}.

Practice playeasy

A number cube is rolled once. What is the probability of rolling an even number?

Three of the six faces (2,4,62, 4, 6) are even, so P=36=12P = \dfrac{3}{6} = \dfrac{1}{2}.

Practice playeasy

The whole numbers 11 through 2424 were each written on separate cards. Those 2424 cards were placed in a hat. One card will be randomly drawn from this hat. What is the probability that the card will show a number greater than 1515?

Numbers greater than 1515 from 11 to 2424 are 16,17,18,19,20,21,22,23,2416, 17, 18, 19, 20, 21, 22, 23, 24, giving 99 favorable outcomes: P=924=38P = \tfrac{9}{24} = \tfrac{3}{8}.

Practice playeasy

What is the probability of the spinner landing on a shaded section (5 of 8)? Give a simplified fraction.

P=favorabletotal=58=58P = \dfrac{\text{favorable}}{\text{total}} = \dfrac{5}{8} = \dfrac{5}{8}.

Practice playeasy

In a random sample of 30, 9 were left-handed students. Estimate how many of 300 are left-handed in the whole population.

Proportion =930= \dfrac{9}{30}. Estimate =930×300=90= \dfrac{9}{30} \times 300 = 90.

Practice playmedium

A standard six-sided number cube is rolled twice. What is the probability of rolling a 44 on the first roll and an even number on the second roll?

P(4 on first roll)=16P(4\text{ on first roll}) = \dfrac{1}{6} and P(even on second roll)=36=12P(\text{even on second roll}) = \dfrac{3}{6} = \dfrac{1}{2}. So P(both)=16×12=112P(\text{both}) = \dfrac{1}{6} \times \dfrac{1}{2} = \dfrac{1}{12}.

Practice playeasy

Two fair coins are flipped. How many outcomes are in the sample space?

Each coin has 22 outcomes, so the sample space has 2×2=42 \times 2 = 4 outcomes: HH, HT, TH, TT.

Keep practicing

Turn statistics and probability into game time.

The NDSA placement starts with this test's real coverage map and finds the right difficulty.