NDSA Grade 7 Geometry. Practice it free.

Solves problems involving scale drawings, angle relationships, and surface area/volume. This Grade 7 reporting domain maps to 9 practice skills and 8 representative questions from the playable bank.

Grade 77.G9 mapped skills
What the test measures

Geometry skills

  1. Solve problems involving scale drawings of geometric figures, including computing actual lengths and areas from a scale drawing.

  2. Draw, construct, and describe geometrical figures and describe the relationships between them.

  3. Solve real-life and mathematical problems involving angle measure, area, surface area, and volume.

Standards basis

North Dakota State Content Standards for Mathematics — North Dakota

How the NDSA reports it

North Dakota administered its own state assessment program (the NDSA, a Cambium computer-adaptive test in grades 3-8 and 10; replaced by ND A+ beginning spring 2025). An official NDSA mathematics public-facing CAT blueprint (Cambium/NDDPI, Oct 2020) does exist and lists per-grade reporting categories with percentage ranges, but its full per-grade table could not be retrieved character-for-character from a citable primary source for transcription here (the Cambium content CDN blocks programmatic access). The NDSA reporting categories are the CCSS-M grade-level domains: the assessment was built on North Dakota's 2017 math standards, which are verbatim CCSS-M organized by grade-level domains. The coverage map below uses North Dakota's 2023-standards-style domain/standard codes (e.g. 3.AR.OA) but the skill content is CCSS-M.

Blueprint & weighting

An official NDSA mathematics CAT blueprint (Cambium/NDDPI public-facing CAT version, Oct 2020) publishes per-grade reporting-category percentage ranges (e.g. grade 3 Operations and Algebraic Thinking ~31-34%, Number and Operations in Base Ten ~22-24%; grade 6 groups Ratios & Proportional Relationships and The Number System ~28-34% and Expressions and Equations ~25-29%). The complete per-grade table could not be retrieved verbatim from a citable primary source (the Cambium content CDN returns HTTP 403 to programmatic fetches), so domain weights in the mapping are left null rather than transcribing partial/uncertain figures or splitting blueprint percentages across the grade-6+ domain groupings.

Try it now

8 free questions · 0/0 correct

Practice playeasy

A cylinder has r2=9r^2 = 9 and height 33. Using π=3\pi = 3, what is its volume?

V=πr2h=3×9×3=81V = \pi r^2 h = 3 \times 9 \times 3 = 81.

Practice playeasy

Two angles are complementary. One measures 10°10°. What is the other?

9010=80°90 - 10 = 80°.

Practice playeasy

A circle has a radius of 88 inches. What is the circumference, in inches, of the circle?

The circumference of a circle is C=2πrC = 2\pi r. Substitute r=8r = 8: C=2π(8)=16π.C = 2\pi(8) = 16\pi\textsf{.}

Practice playeasy

A circle has diameter 66. Using π=3\pi = 3, what is its circumference?

C=πd=3×6=18C = \pi d = 3 \times 6 = 18.

Practice playeasy

Similar triangles STUSTU and VWXVWX have areas 3636 and 9.9\textsf{.} Side STST corresponds to side VW,VW\textsf{,} and ST=12.ST = 12\textsf{.} What is the length of VW?VW\textsf{?}

The scale factor from STU\triangle STU to VWX\triangle VWX satisfies k2=936=14,k^{2} = \dfrac{9}{36} = \dfrac{1}{4}\textsf{,} so k=12.k = \dfrac{1}{2}\textsf{.} Then VW=1212=6.VW = 12 \cdot \dfrac{1}{2} = 6\textsf{.}

Practice playhard

A rectangular prism has volume 160160 cubic inches and height 55 inches. The length is twice the width. What is the length, in inches?

V=whV = \ell w h and =2w\ell = 2w, so 160=(2w)(w)(5)=10w2160 = (2w)(w)(5) = 10w^2. Then w2=16w^2 = 16, so w=4w = 4 and =8 in.\ell = 8\text{ in}\textsf{.}

Practice playmedium

A shipping company uses closed rectangular cartons that measure 66 centimeters by 44 centimeters by 55 centimeters. What is the total exterior surface area, in square centimeters, of one carton?

Use SA=2lw+2lh+2whSA = 2lw + 2lh + 2wh with l=6l = 6, w=4w = 4, and h=5h = 5. Then SA=2(6)(4)+2(6)(5)+2(4)(5)=48+60+40=148SA = 2(6)(4) + 2(6)(5) + 2(4)(5) = 48 + 60 + 40 = 148 square centimeters.

Practice playeasy

Find the surface area of a sphere with radius 11. Use π=3\pi = 3.

SA=4πr2=4×3×1=12SA = 4 \pi r^{2} = 4 \times 3 \times 1 = 12.

Keep practicing

Turn geometry into game time.

The NDSA placement starts with this test's real coverage map and finds the right difficulty.