NJSLA Algebra II Linear, Quadratic, and Exponential Models. Practice it free.

Construct and compare linear, quadratic, and exponential models and solve problems. This Algebra II reporting domain maps to 10 practice skills and 8 representative questions from the playable bank.

Algebra IIF-LE10 mapped skills
What the test measures

Linear, Quadratic, and Exponential Models skills

  1. F.LE.A.1-4 Linear vs exponential, constructing models, and interpreting parameters

  2. F.LE.B.5-6 Average rate of change and model features

Standards basis

New Jersey Student Learning Standards for Mathematics (NJSLS-M), aligned to Common Core State Standards for Mathematics (CCSS-M) — New Jersey

How the NJSLA reports it

NJSLA math is built on the New Jersey Student Learning Standards for Mathematics, which closely follow the Common Core domain structure and progressions. The assessment is organized by grade-level and end-of-course reporting aligned to those standards rather than by a separate proprietary framework.

Blueprint & weighting

NJDOE publishes statewide assessment administration information and grade/course coverage, but no official public math-domain weighting blueprint was located in the retrieved primary materials.

Try it now

8 free questions · 0/0 correct

Practice playmedium

A forest preserve had 4,0004{,}000 acres of woodland in 20102010. Each year from 20102010 through 20202020, a model estimates that the woodland area decreased by 5%5\% of the area the previous year. Which equation defines this model, where a(t)a(t) is the estimated woodland area, in acres, tt years after 20102010?

The starting area is 4,0004{,}000 acres, and a 5%5\% yearly decrease means multiplying by 0.950.95 each year, so a(t)=4,000(0.95)ta(t) = 4{,}000(0.95)^t.

Practice playeasy

The function hh is defined by h(t)=125(1.18)th(t) = 125(1.18)^t. The function hh models the number of members in a club, where tt is the number of years after the club was founded. According to the model, what is the estimated number of members when the club was founded?

When the club was founded, t=0t = 0. So h(0)=125(1.18)0=125h(0) = 125(1.18)^0 = 125 members.

Practice playeasy

A substance has a half-life of 44 years. What fraction remains after 1212 years?

12÷4=312 \div 4 = 3 half-lives. Remaining: (12)3=18\left(\dfrac{1}{2}\right)^{3} = \dfrac{1}{8}.

Practice playeasy

The function rr is defined by r(t)=60(1.09)tr(t) = 60(1.09)^{t}. The function models the number of registered runners in a charity race tt years after the first race. Which statement is the best interpretation of the growth factor 1.091.09 in this context?

The growth factor is 1.091.09. Each time tt increases by 11, the number of runners is multiplied by 1.091.09. That means each year the number of runners is 109%109\% of the previous year's number, a 9%9\% increase.

Practice playeasy

The given equation represents the weight WW, in ounces, where nn represents the number of identical snack bags.

W=3.2nW = 3.2n

Which of the following is the best interpretation of
3.23.2 in this context?

In W=3.2nW = 3.2n, the number 3.23.2 is the weight in ounces of one snack bag.

Practice playeasy

A bakery has 5050 ounces of flour to make muffins and cookies. The baker uses the equation 4m+2k=504m + 2k = 50 to figure out how many muffins, mm, and how many cookies, kk, can be made. Which is the best interpretation of the number 44 in this equation?

Each muffin uses 44 ounces of flour, so the number of muffins is multiplied by 44.

Practice playeasy

Taxi cost, in dollars, after xx miles:
xf(x)16210314418\begin{array}{c|c} x & f(x) \\ \hline 1 & 6 \\ 2 & 10 \\ 3 & 14 \\ 4 & 18 \end{array}
The cost is
f(x)=mx+2.f(x)=mx+2\textsf{.} What is m?m\textsf{?}

Slope-intercept form is f(x)=mx+b.f(x) = mx + b\textsf{.} The cost increases by $4\text{\char36}4 per mile, so m=4.m = 4\textsf{.}

Practice playmedium

The table shows values of a linear function n.n\textsf{.}
x2468n(x)11151923\begin{array}{c|cccc} x & 2 & 4 & 6 & 8 \\ \hline n(x) & 11 & 15 & 19 & 23 \end{array}
Which of the following is
n(x)?n(x)\textsf{?}

From x=2x = 2 to x=4,x = 4\textsf{,} n(x)n(x) increases by 4,4\textsf{,} so the constant rate is 42=2.\dfrac{4}{2} = 2\textsf{.} Using the point (2,11)(2, 11) gives 2(2)+b=11,2(2) + b = 11\textsf{,} so b=7.b = 7\textsf{.} Therefore n(x)=2x+7.n(x) = 2x + 7\textsf{.}

Keep practicing

Turn linear, quadratic, and exponential models into game time.

The NJSLA placement starts with this test's real coverage map and finds the right difficulty.