NJSLA Algebra II Making Inferences and Justifying Conclusions. Practice it free.

Understand and evaluate random processes underlying statistical experiments; make inferences and justify conclusions from sample surveys, experiments, and observational studies. This Algebra II reporting domain maps to 1 practice skill and 8 representative questions from the playable bank.

Algebra IIS-IC1 mapped skills
What the test measures

Making Inferences and Justifying Conclusions skills

  1. S.IC.A.1-2 Statistical inference and model checking

  2. S.IC.B.3-6 Sampling, experiments, observational studies, and evaluation of reports

Standards basis

New Jersey Student Learning Standards for Mathematics (NJSLS-M), aligned to Common Core State Standards for Mathematics (CCSS-M) — New Jersey

How the NJSLA reports it

NJSLA math is built on the New Jersey Student Learning Standards for Mathematics, which closely follow the Common Core domain structure and progressions. The assessment is organized by grade-level and end-of-course reporting aligned to those standards rather than by a separate proprietary framework.

Blueprint & weighting

NJDOE publishes statewide assessment administration information and grade/course coverage, but no official public math-domain weighting blueprint was located in the retrieved primary materials.

Practice by skill

Topics mapped to this domain

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8 free questions · 0/0 correct

Practice playmedium

The mass of a chemical sample is modeled by m(x)=480(0.92)xm(x)=480(0.92)^x, where xx is the number of days after an initial measurement. According to the model, by what percent does the mass of the sample decrease each day?

The factor 0.920.92 means that each day the mass is 92%92\% of the previous day's mass, so the daily decrease is 100%92%=8%100\% - 92\% = 8\%.

Practice playmedium

An online store's weekly visitors are modeled by v(w)=1,250(1.08)wv(w)=1{,}250(1.08)^w, where ww is the number of weeks after a launch campaign begins. According to the model, how many visitors does the store have 22 weeks after the campaign begins?

Substitute w=2w=2: v(2)=1,250(1.08)2=1,250(1.1664)=1,458v(2)=1{,}250(1.08)^2=1{,}250(1.1664)=1{,}458.

Practice playmedium

A cold front is expected to reduce a reservoir's algae volume by 34\frac{3}{4} of its previous amount each week. The volume is 640640 cubic meters at the start of week 00. Which equation models the algae volume A(w)A(w), in cubic meters, after ww weeks?

A reduction of 34\frac{3}{4} of the previous volume leaves a remaining factor of 14\frac{1}{4} each week. Starting from 640640, the volume after ww weeks is A(w)=640(14)wA(w)=640\left(\frac{1}{4}\right)^w.

Practice playeasy

A librarian checked 4040 books selected at random from a collection of 800800 books. She found that 1414 of the books in the sample were fiction. Based on the sample, which of the following is the best estimate of the number of fiction books in the collection?

The sample proportion is 1440=720\dfrac{14}{40} = \dfrac{7}{20}. The best estimate for the collection is 720×800=280\dfrac{7}{20} \times 800 = 280 books.

Practice playeasy

A ball is tossed upward from a platform. The equation h=4.9t2+14t+21h = -4.9t^2 + 14t + 21 represents this situation, where hh is the height of the ball above the ground, in meters, tt seconds after it is tossed. According to the equation, what is the height, in meters, of the platform from which the ball was tossed?

At the moment of release, t=0t = 0. Substituting gives h=4.9(0)2+14(0)+21=21h = -4.9(0)^2 + 14(0) + 21 = 21 meters.

Practice playeasy

A stone is thrown upward from the edge of a cliff overlooking a valley. The equation s=5t2+11t+16s = -5t^2 + 11t + 16 models the stone's height ss, in meters, above the valley floor tt seconds after it is thrown. According to the equation, what is the height, in meters, of the cliff edge above the valley floor?

When the stone is thrown from the cliff edge, t=0t = 0. Then s=5(0)2+11(0)+16=16s = -5(0)^2 + 11(0) + 16 = 16 meters above the valley floor.

Practice playeasy

A football is kicked from a stadium deck. The equation d=16t2+48t+64d = -16t^2 + 48t + 64 represents this situation, where dd is the height of the football above the field, in feet, tt seconds after it is kicked. According to the equation, what is the height, in feet, of the deck from which the football was kicked?

When the kick occurs, t=0t = 0. Substituting gives d=16(0)2+48(0)+64=64d = -16(0)^2 + 48(0) + 64 = 64 feet.

Practice playmedium

A grocer surveyed 2525 customers selected at random and found that 1515 of them purchased at least one organic item. Based on the survey, which of the following is the best estimate of the number of customers out of 500500 who would purchase at least one organic item?

The sample proportion is 1525=35\dfrac{15}{25} = \dfrac{3}{5}. The best estimate for 500500 customers is 35×500=300\dfrac{3}{5} \times 500 = 300 customers.

Keep practicing

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