NJSLA Geometry Similarity, Right Triangles, and Trigonometry. Practice it free.

Understand similarity in terms of similarity transformations; prove theorems involving similarity; define trigonometric ratios and solve problems involving right triangles. This Geometry reporting domain maps to 5 practice skills and 8 representative questions from the playable bank.

GeometryG-SRT5 mapped skills
What the test measures

Similarity, Right Triangles, and Trigonometry skills

  1. G.SRT.A.1-3 Similarity transformations and AA criterion

  2. G.SRT.B.4-5 Triangle similarity and proof applications

  3. G.SRT.C.6-8 Trigonometric ratios and right triangle applications

Standards basis

New Jersey Student Learning Standards for Mathematics (NJSLS-M), aligned to Common Core State Standards for Mathematics (CCSS-M) — New Jersey

How the NJSLA reports it

NJSLA math is built on the New Jersey Student Learning Standards for Mathematics, which closely follow the Common Core domain structure and progressions. The assessment is organized by grade-level and end-of-course reporting aligned to those standards rather than by a separate proprietary framework.

Blueprint & weighting

NJDOE publishes statewide assessment administration information and grade/course coverage, but no official public math-domain weighting blueprint was located in the retrieved primary materials.

Try it now

8 free questions · 0/0 correct

Practice playeasy

In isosceles △DEF\triangle DEF with DE≅DFDE \cong DF, each base angle measures 58∘58^{\circ}. Which side has the greatest length?

The base angles at EE and FF each measure 58∘58^{\circ}, so the vertex angle at DD is 180∘−2(58∘)=64∘180^{\circ} - 2(58^{\circ}) = 64^{\circ}. The greatest angle is at DD, so the opposite side EFEF is the longest.

Practice playeasy

In a right triangle, sin⁡θ=1213\sin\theta = \dfrac{12}{13} and tan⁡θ=125\tan\theta = \dfrac{12}{5}. What is cos⁡θ\cos\theta?

cos⁡θ=sin⁡θtan⁡θ=1213125=1213⋅512=513\cos\theta = \dfrac{\sin\theta}{\tan\theta} = \dfrac{\dfrac{12}{13}}{\dfrac{12}{5}} = \dfrac{12}{13} \cdot \dfrac{5}{12} = \dfrac{5}{13}.

Practice playmedium

A student who is 44 feet tall casts a shadow 55 feet long. A building casts a shadow 6565 feet long at the same time. How tall is the building, in feet?

Set up 45=h65\dfrac{4}{5} = \dfrac{h}{65}. Cross-multiply: 5h=2605h = 260, so h=52h = 52 feet.

Practice playeasy

In a 30∘30^{\circ}-60∘60^{\circ}-90∘90^{\circ} triangle, the short leg is 10.10\textsf{.} What is the hypotenuse?

In a 30∘30^{\circ}-60∘60^{\circ}-90∘90^{\circ} triangle, the hypotenuse is twice the short leg: 2×10=20.2 \times 10 = 20\textsf{.}

Practice playeasy

In a 4545-4545-9090 triangle one leg is 1515. What is the other leg?

Both legs of a 4545-4545-9090 triangle are equal, so the other leg is 1515.

Practice playeasy

In the standard coordinate plane, how many points are both 55 units from the origin and also exactly 33 units from the line x=0x = 0?

Points 55 units from the origin satisfy x2+y2=25x^{2} + y^{2} = 25. Being exactly 33 units from x=0x = 0 means ∣x∣=3|x| = 3, so x=3x = 3 or x=−3x = -3. Substituting gives y2=16y^{2} = 16, so y=4y = 4 or y=−4y = -4 for each xx-value. That yields (3,4)(3, 4), (3,−4)(3, -4), (−3,4)(-3, 4), and (−3,−4)(-3, -4): 44 points.

Practice playeasy

In a right triangle, cos⁡α=513\cos\alpha = \dfrac{5}{13} and tan⁡α=125\tan\alpha = \dfrac{12}{5}. What is sin⁡α\sin\alpha?

sin⁡α=tan⁡α⋅cos⁡α=125⋅513=1213\sin\alpha = \tan\alpha \cdot \cos\alpha = \dfrac{12}{5} \cdot \dfrac{5}{13} = \dfrac{12}{13}.

Practice playmedium

At a zoo, a keeper who is 66 feet tall casts a shadow 44 feet long. A giraffe standing nearby casts a shadow at the same time. If the giraffe is 2121 feet tall, how long is its shadow, in feet?

Use 64=21s\dfrac{6}{4} = \dfrac{21}{s}. Cross-multiply: 6s=846s = 84, so s=14s = 14 feet.

Keep practicing

Turn similarity, right triangles, and trigonometry into game time.

The NJSLA placement starts with this test's real coverage map and finds the right difficulty.