PARCC Algebra I Interpreting Functions. Practice it free.

Students interpret functions that arise in applications in terms of the context and analyze key features of graphs and tables. This Algebra I reporting domain maps to 11 practice skills and 8 representative questions from the playable bank.

Algebra I11 mapped skills
What the test measures

Interpreting Functions skills

  1. Understand the concept of a function and use function notation

  2. Interpret functions that arise in applications in terms of the context

  3. Analyze functions using different representations

Standards basis

Common Core State Standards for Mathematics (CCSS-M) / PARCC Model Content Frameworks — national

How the PARCC reports it

PARCC was a multistate assessment system built around the Common Core-era PARCC mathematics model content frameworks rather than a separate proprietary standards set. Its math structure is organized by grade/course and aligned to CCSS-M content categories and model content frameworks.

Blueprint & weighting

No single published PARCC weighting table was located in the accessible sources used here.

Try it now

8 free questions · 0/0 correct

Practice playeasy

The function ff is defined by f(x)=7x4f(x) = 7x - 4. What is the value of f(x)f(x) when x=3x = 3?

Substitute x=3x = 3: f(3)=7(3)4=214=17f(3) = 7(3) - 4 = 21 - 4 = 17.

Practice playeasy

The function ff is defined by f(x)=2x+1f(x) = \sqrt{2x + 1}. What is the value of f(x)f(x) when x=4x = 4?

Substitute x=4x = 4: f(4)=2(4)+1=9=3f(4) = \sqrt{2(4) + 1} = \sqrt{9} = 3.

Practice playeasy

For the function pp, p(0)=200p(0) = 200. For each increase in xx by 11, the value of p(x)p(x) decreases by 10%10\%. What is the value of p(2)p(2)?

Each step multiplies by 0.900.90. So p(2)=2000.902=2000.81=162p(2) = 200 \cdot 0.90^2 = 200 \cdot 0.81 = 162.

Practice playeasy

g=9m4g = 9 - \dfrac{m}{4}

The equation shown gives the estimated amount of paint
g,g\textsf{,} in gallons, remaining after covering mm square meters of wall, where 0m36.0 \le m \le 36\textsf{.} What is the estimated amount of paint, in gallons, remaining after covering 1212 square meters of wall?

Substitute m=12:m = 12\textsf{:} g=9124=93=6.g = 9 - \dfrac{12}{4} = 9 - 3 = 6\textsf{.} The estimated amount remaining is 66 gallons.

Practice playmedium

At what xx-value does the graph of y=3(x5)2(x+8)y = 3(x - 5)^2(x + 8) intercept the xx-axis?

Set y=0y = 0: 3(x5)2(x+8)=03(x - 5)^2(x + 8) = 0. The constant 303 \neq 0, so the zeros are x=5x = 5 (from the repeated factor) and x=8x = -8. Among the choices, only 55 is an x-coordinate of an x-intercept.

Practice playmedium

The function hh is defined by h(t)=16t2+64t+5h(t) = -16t^{2} + 64t + 5. The function models the height, in feet, of a baseball tt seconds after it is hit. Which of the following is the best interpretation of the statement "h(2)h(2) is equal to 6969" in this context?

In this model, tt is seconds after the ball is hit and h(t)h(t) is height in feet. So h(2)=69h(2) = 69 means that 22 seconds after the ball is hit, its height is 6969 feet.

Practice playeasy

A warehouse tracks inventory with I(t)=2t2+6t+85I(t) = -2t^2 + 6t + 85, where I(t)I(t) is the number of units on hand tt weeks after a shipment arrives. According to the model, how many units were on hand when the shipment arrived?

When the shipment arrived, t=0t = 0. So I(0)=2(0)2+6(0)+85=85I(0) = -2(0)^2 + 6(0) + 85 = 85 units.

Practice playeasy

f(x)=(x2)2+10f(x) = (x - 2)^2 + 10

The function
ff is defined by the given equation. For what value of xx does f(x)f(x) reach its minimum?

The equation is in vertex form f(x)=a(xh)2+kf(x) = a(x - h)^2 + k with a=1>0a = 1 > 0, so the graph opens upward and the minimum occurs at the vertex. Here h=2h = 2, so the vertex is at x=2x = 2. Therefore, f(x)f(x) reaches its minimum when x=2x = 2.

Keep practicing

Turn interpreting functions into game time.

The PARCC placement starts with this test's real coverage map and finds the right difficulty.