Georgia Milestones Algebra I Interpreting Functions. Practice it free.

Students understand, evaluate, and interpret functions and function notation. This Algebra I reporting domain maps to 13 practice skills and 8 representative questions from the playable bank.

Algebra I13 mapped skills
What the test measures

Interpreting Functions skills

  1. Understand the concept of a function and use function notation

  2. Interpret functions that arise in applications in terms of the context

  3. Analyze functions using different representations

Standards basis

Georgia Standards of Excellence (state-adopted content standards) — Georgia

How the Georgia Milestones reports it

Georgia Milestones is Georgia’s own statewide assessment system, aligned to Georgia’s state-adopted content standards rather than a shared national test framework. The official page says it measures knowledge and skills in the state-adopted standards for mathematics across grades 3 through high school ([Georgia Department of Education](https://gadoe.org/assessment-accountability/georgia-milestones/)).

Blueprint & weighting

Not published on the official Georgia Milestones overview page reviewed here.

Try it now

8 free questions · 0/0 correct

Practice playeasy

The function ff is defined by f(x)=x2−10f(x) = x^{2} - 10. What is the value of f(x)f(x) when x=6x = 6?

Substitute x=6x = 6: f(6)=62−10=36−10=26f(6) = 6^{2} - 10 = 36 - 10 = 26.

Practice playeasy

The function ff is defined by f(x)=x+5f(x) = \sqrt{x + 5}. What is the value of f(x)f(x) when x=11x = 11?

Substitute x=11x = 11: f(11)=11+5=16=4f(11) = \sqrt{11 + 5} = \sqrt{16} = 4.

Practice playeasy

For the function ff, f(0)=160f(0) = 160. For each increase in xx by 11, the value of f(x)f(x) decreases by 50%50\%. What is the value of f(3)f(3)?

A decrease of 50%50\% multiplies by 0.500.50 each step. So f(3)=160⋅0.503=160⋅0.125=20f(3) = 160 \cdot 0.50^3 = 160 \cdot 0.125 = 20.

Practice playeasy

b=100−4hb = 100 - 4h

The equation shown gives the estimated battery charge
b,b\textsf{,} as a percent, remaining on a laptop after hh hours of use, where 0≤h≤20.0 \le h \le 20\textsf{.} What is the estimated battery charge, as a percent, remaining on the laptop after 1212 hours of use?

Substitute h=12:h = 12\textsf{:} b=100−4(12)=100−48=52.b = 100 - 4(12) = 100 - 48 = 52\textsf{.} The estimated charge remaining is 5252 percent.

Practice playeasy

For which value of xx does the graph of y=−(x+8)(x−2)y = -(x + 8)(x - 2) meet the xx-axis?

Set y=0y = 0: −(x+8)(x−2)=0-(x + 8)(x - 2) = 0. The factor −1-1 is nonzero, so the zeros come from x+8=0⇒x=−8x + 8 = 0 \Rightarrow x = -8 and x−2=0⇒x=2x - 2 = 0 \Rightarrow x = 2. Of the choices, −8-8 is an x-coordinate of an x-intercept.

Practice playeasy

The equation of a line is 5x+6y=−120.5x + 6y = -120\textsf{.} What is the xx-intercept of the line?

The xx-intercept is the value of xx when y=0.y = 0\textsf{.} Substituting gives 5x=−120,5x = -120\textsf{,} so x=−24.x = -24\textsf{.}

Practice playmedium

The function TT is defined by T(d)=−4d+86T(d) = -4d + 86. The function models the outdoor temperature, in degrees Fahrenheit, dd days after a cold front arrives. The domain of the function is 0≤d≤100 \le d \le 10. Which of the following is the best interpretation of the statement "T(3)T(3) is equal to 7474" in this context?

In this model, dd is days after the cold front arrives and T(d)T(d) is the temperature in degrees Fahrenheit. So T(3)=74T(3) = 74 means that 33 days after the cold front arrives, the temperature is 7474 degrees Fahrenheit.

Practice playeasy

The equation of a line is y+2=23(x+7).y + 2 = \dfrac{2}{3}(x + 7)\textsf{.} Which point is used to write this equation?

Point-slope form is y−y1=m(x−x1).y - y_1 = m(x - x_1)\textsf{.} The given point is (x1,y1)=(−7,−2).(x_1, y_1) = (-7, -2)\textsf{.}

Keep practicing

Turn interpreting functions into game time.

The Georgia Milestones placement starts with this test's real coverage map and finds the right difficulty.