Grade 9 · Algebra & functions

Monomial expression multiplication (SAT) practice

Monomial expression multiplication (SAT) is a grade 9 math skill aligned to Common Core standard HSA.SSE.A.2: use the structure of an expression to identify ways to rewrite it. Below are 8 practice questions with answers and step-by-step explanations, drawn from the 10 monomial expression multiplication (sat) problems our math games drill.

CCSS HSA.SSE.A.210 questions in the bank
Sample questions

Try 8 for free

Question 1easy

Which expression is equivalent to (a3b4)(a1b2)(a^3 b^{-4})(a^{-1} b^2)?

Add exponents on matching variables: a3+(1)b4+2=a2b2a^{3+(-1)} b^{-4+2} = a^2 b^{-2}.

Question 2easy

Which expression is equivalent to (p5q2r3)(pq4r2)(p^5 q^2 r^{-3})(p q^4 r^2)?

Add exponents on matching variables: p5+1q2+4r3+2=p6q6r1p^{5+1} q^{2+4} r^{-3+2} = p^6 q^6 r^{-1}.

Question 3medium

Which expression is equivalent to (m2n3p4)(m1n2p1)(m^2 n^{-3} p^4)(m^{-1} n^2 p^{-1})?

Add exponents on each variable: m2+(1)n3+2p4+(1)=mn1p3m^{2+(-1)} n^{-3+2} p^{4+(-1)} = m n^{-1} p^3.

Question 4medium

Which expression is equivalent to (x5y2z3)(x3y1z4)(x^{-5} y^2 z^3)(x^3 y^{-1} z^{-4})?

Add exponents on matching variables: x5+3y2+(1)z3+(4)=x2yz1x^{-5+3} y^{2+(-1)} z^{3+(-4)} = x^{-2} y z^{-1}.

Question 5medium

Which expression is equivalent to (x4y2)(x3y5)(-x^4 y^{-2})(x^{-3} y^5)?

The leading negative gives coefficient 1-1. Add exponents: x4+(3)y2+5=xy3x^{4+(-3)} y^{-2+5} = -x y^3.

Question 6medium

Which expression is equivalent to (2a3b2c1)(a2b4c5)(2a^3 b^2 c^{-1})(-a^{-2} b^{-4} c^5)?

Multiply coefficients: (2)(1)=2(2)(-1) = -2. Add exponents: a3+(2)b2+(4)c1+5=2ab2c4a^{3+(-2)} b^{2+(-4)} c^{-1+5} = -2a b^{-2} c^4.

Question 7medium

Which expression is equivalent to (3x2yz4)(x3y2z3)(3x^{-2} y z^4)(x^3 y^{-2} z^{-3})?

Multiply coefficients: 31=33 \cdot 1 = 3. Add exponents: x2+3y1+(2)z4+(3)=3xy1zx^{-2+3} y^{1+(-2)} z^{4+(-3)} = 3x y^{-1} z.

Question 8medium

Which expression is equivalent to (3m4n2)(2m3n5)(-3m^{-4} n^2)(2m^3 n^{-5})?

Multiply coefficients: (3)(2)=6(-3)(2) = -6. Add exponents: m4+3n2+(5)=6m1n3m^{-4+3} n^{2+(-5)} = -6m^{-1} n^{-3}.

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