Monomial expression multiplication (SAT). Game on.

Monomial expression multiplication (SAT) is a grade 9 math skill aligned to Common Core standard HSA.APR.A.1: understand that polynomials form a system analogous to the integers: they are closed under addition, subtraction, and multiplication; add, subtract, and multiply polynomials. Below are 8 practice questions with answers and step-by-step explanations, drawn from the 20 monomial expression multiplication (sat) problems our math games drill.

CCSS HSA.APR.A.120 questions in the bank
Kickoff

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Warm-upeasy

Which expression is equivalent to (5x)(3x)?(5x)(3x)\textsf{?}

Multiply the coefficients: 53=15.5 \cdot 3 = 15\textsf{.} Add the exponents on xx: x1+1=x2.x^{1+1} = x^{2}\textsf{.} So the product is 15x2.15x^{2}\textsf{.}

Mid-gameeasy

Which expression is equivalent to (a3b4)(a1b2)?(a^3 b^{-4})(a^{-1} b^2)\textsf{?}

Add exponents on matching variables: a3+(1)b4+2=a2b2.a^{3+(-1)} b^{-4+2} = a^2 b^{-2}\textsf{.}

Mid-gameeasy

Which expression is equivalent to (4ab)(2a)?(4ab)(2a)\textsf{?}

Multiply the coefficients: 42=8.4 \cdot 2 = 8\textsf{.} Add the exponents on aa: a1+1=a2.a^{1+1} = a^{2}\textsf{.} The factor bb appears once, so the product is 8a2b.8a^{2}b\textsf{.}

Mid-gameeasy

Which expression is equivalent to (p5q2r3)(pq4r2)?(p^5 q^2 r^{-3})(p q^4 r^2)\textsf{?}

Add exponents on matching variables: p5+1q2+4r3+2=p6q6r1.p^{5+1} q^{2+4} r^{-3+2} = p^6 q^6 r^{-1}\textsf{.}

Mid-gameeasy

Which expression is equivalent to (6mn)(n)(2m)?(6mn)(n)(2m)\textsf{?}

Multiply the coefficients: 612=12.6 \cdot 1 \cdot 2 = 12\textsf{.} Add the exponents on mm and on nn: m1+1n1+1=m2n2.m^{1+1} n^{1+1} = m^{2} n^{2}\textsf{.} So the product is 12m2n2.12m^{2}n^{2}\textsf{.}

Mid-gameeasy

Which expression is equivalent to (3x2)(4x)?(3x^{2})(4x)\textsf{?}

Multiply the coefficients: 34=12.3 \cdot 4 = 12\textsf{.} Add the exponents on xx: x2+1=x3.x^{2+1} = x^{3}\textsf{.} So the product is 12x3.12x^{3}\textsf{.}

Mid-gameeasy

Which expression is equivalent to (2yz)(5y)(4)?(2yz)(5y)(4)\textsf{?}

Multiply the coefficients: 254=40.2 \cdot 5 \cdot 4 = 40\textsf{.} Add the exponents on yy: y1+1=y2.y^{1+1} = y^{2}\textsf{.} The factor zz appears once, so the product is 40y2z.40y^{2}z\textsf{.}

Buzzer beatereasy

Which expression is equivalent to (7p)(pq)(2q)?(7p)(pq)(2q)\textsf{?}

Multiply the coefficients: 712=14.7 \cdot 1 \cdot 2 = 14\textsf{.} Add the exponents on pp and on qq: p1+1q1+1=p2q2.p^{1+1} q^{1+1} = p^{2} q^{2}\textsf{.} So the product is 14p2q2.14p^{2}q^{2}\textsf{.}

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