PSSA Grade 8 Geometry. Practice it free.

The legs are $16$ and $30$. By the Pythagorean theorem, $16^{2} + 30^{2} = 256 + 900 = 1{,}156$, so the hypotenuse is $\sqrt{1{,}156} = 34$.

$9^{2} + 12^{2} = 81 + 144 = 225$, so the hypotenuse is $\sqrt{225} = 15\textsf{.}$

The string is the hypotenuse: $25^{2} - 7^{2} = 625 - 49 = 576$, so the height is $\sqrt{576} = 24$ meters.

Area $A = \ell w$, so $120 = 8w$ and $w = 15$. The diagonal is the hypotenuse of a right triangle with legs $8$ and $15$: $\sqrt{8^2 + 15^2} = \sqrt{64 + 225} = \sqrt{289} = 17\text{ cm}\textsf{.}$

$V = \pi r^2 h = 3 \times 4 \times 4 = 48$.

Both points have $x = 5$, so the length is $|9 - (-3)| = 12$.

Together the congruent angles measure $2 \times 38.2^{\circ} = 76.4^{\circ}$, so $\angle M = 180^{\circ} - 76.4^{\circ} = 103.6^{\circ}$.

The interior angle sum of a quadrilateral is $360°$.