Contingency Tables Quiz
The question sheet
Reveal any answer as you study-
According to the cell phone study, what is the total number of people in the sample?
- 450
- 685
- 755
- 305
Reveal answer
Answer: 755
Source evidence
PDF page 201: The total number of people in the sample is 755. The row totals are 305 and 450. The column totals are 70 and
PDF page 201: Speeding violation in the No speeding violation in the Total last year last year Uses cell phone while driving 25 280 305 Does not use cell phone while 45 405 450 driving Total 70 685 755
-
In the speeding violation table, how many cell phone users had no violation in the last year?
- 405
- 25
- 45
- 280
Reveal answer
Answer: 280
Source evidence
PDF page 201: Speeding violation in the No speeding violation in the Total last year last year Uses cell phone while driving 25 280 305 Does not use cell phone while 45 405 450 driving Total 70 685 755
-
What is P(Driver is a cell phone user) in the speeding study?
- 450/755
- 685/755
- 70/755
- 305/755
Reveal answer
Answer: 305/755
Source evidence
PDF page 202: Solutions: number of cell phone users 305 a. = total number in study 755
-
What is P(driver had no violation in the last year)?
- 685/755
- 70/755
- 280/755
- 305/755
Reveal answer
Answer: 685/755
Source evidence
PDF page 202: number that had no violation 685 b. = total number in study 755
-
What is P(cell phone user GIVEN driver had a violation)?
- 280/305
- 25/305
- 45/70
- 25/70
Reveal answer
Answer: 25/70
Source evidence
PDF page 202: 25 e. (The sample space is reduced to the number of drivers who had a violation.) 70
-
What is P(no violation GIVEN driver was not a cell phone user)?
- 405/685
- 280/305
- 405/450
- 45/450
Reveal answer
Answer: 405/450
Source evidence
PDF page 202: 405 (The sample space is reduced to the number of drivers who were not cell phone users.) f. 450
-
What does a contingency table display?
- A single variable's frequencies
- Time series over years
- Sample values for two variables
- Only conditional probabilities
Reveal answer
Answer: Sample values for two variables
Source evidence
PDF page 201: A contingency table provides a way of portraying data that can facilitate calculating probabilities. The table helps in determining conditional probabilities quite easily. The table displays sample values in relation to two different variables that may be dependent or contingent on one another. Later on, we will use contingency tables again, but in another manner.
-
A contingency table is especially helpful in determining what?
- Sample sizes
- Correlation coefficients
- Standard deviations
- Conditional probabilities
Reveal answer
Answer: Conditional probabilities
Source evidence
PDF page 201: A contingency table provides a way of portraying data that can facilitate calculating probabilities. The table helps in determining conditional probabilities quite easily. The table displays sample values in relation to two different variables that may be dependent or contingent on one another. Later on, we will use contingency tables again, but in another manner.
-
In the athlete stretching table, how many athletes stretch in total?
- 286
- 350
- 450
- 800
Reveal answer
Answer: 350
Source evidence
PDF page 202: Stretches 55 295 350 Does not stretch 231 219 450 Total 286 514 800
-
In the stretching table, what is the total sample size?
- 450
- 286
- 800
- 514
Reveal answer
Answer: 800
Source evidence
PDF page 202: Stretches 55 295 350 Does not stretch 231 219 450 Total 286 514 800
-
For the 100 hikers table, how many females were there in total?
- 34
- 55
- 100
- 45
Reveal answer
Answer: 45
Source evidence
PDF page 203: Female 18 16 11 45 Male 16 25 14 55 Total 34 41 25 100
-
In the hiker table, how many people preferred near lakes and streams?
- 41
- 25
- 34
- 100
Reveal answer
Answer: 41
Source evidence
PDF page 203: Female 18 16 11 45 Male 16 25 14 55 Total 34 41 25 100
Introductory Statistics
Introductory Statistics by OpenStax, used under CC BY 4.0. Changes made by Stratacademy.
Make your own — free
Turn any notes into a game in under a minute. Free to start.