Facts About the F Distribution Quiz
The question sheet
Reveal any answer as you study-
For the slicing tomato test, which F distribution was used?
- F4,10
- F2,12
- F3,16
- F10,4
Reveal answer
Answer: F4,10
Source evidence
PDF page 758: Distribution for the test: F4,10
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In the tomato yield ANOVA, what was the test statistic F?
- 2.23
- 0.134
- 0.0248
- 4.4810
Reveal answer
Answer: 4.4810
Source evidence
PDF page 758: Test statistic: F = 4.4810
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For the tomato test, the p-value P(F > 4.481) equaled:
- 0.8759
- 0.05
- 0.0248
- 0.1241
Reveal answer
Answer: 0.0248
Source evidence
PDF page 759: Probability Statement: p-value = P(F > 4.481) = 0.0248.
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In the tomato test with α = 0.05 and p-value = 0.0248, the decision was to:
- Reject H0
- Fail to test H0
- Accept Ha only
- Do not reject H0
Reveal answer
Answer: Reject H0
Source evidence
PDF page 759: Make a decision: Since α > p-value, we reject H0. Conclusion: At the 5% significance level, we have reasonably strong evidence that differences in mean yields for slicing tomato plants grown under different mulching conditions are unlikely to be due to chance alone. We may conclude that at least some of mulches led to different mean yields.
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For the sorority grades test, what distribution was used?
- F4,10
- F16,3
- F2,12
- F3,16
Reveal answer
Answer: F3,16
Source evidence
PDF page 761: Distribution for the test: F3,16
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In the sorority study, how many total samples were there?
- 16
- 4
- 20
- 5
Reveal answer
Answer: 20
Source evidence
PDF page 761: where k = 4 groups and n = 20 samples in total
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For the sorority test, the numerator degrees of freedom equaled:
- 20
- 4
- 3
- 16
Reveal answer
Answer: 3
Source evidence
PDF page 761: df(num)= k – 1 = 4 – 1 = 3
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In the sorority grades test, the calculated F statistic was:
- 4.4810
- 0.1241
- 0.134
- 2.23
Reveal answer
Answer: 2.23
Source evidence
PDF page 761: Calculate the test statistic: F = 2.23 Graph:
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For the sorority test, p-value P(F > 2.23) equaled:
- 0.8759
- 0.1241
- 0.0248
- 0.05
Reveal answer
Answer: 0.1241
Source evidence
PDF page 761: Probability statement: p-value = P(F > 2.23) = 0.1241
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In the sorority test with α = 0.01 and p-value = 0.1241, the decision was to:
- Accept Ha
- Reject Ha
- Cannot reject H0
- Reject H0
Reveal answer
Answer: Cannot reject H0
Source evidence
PDF page 762: α < p-value Make a decision: Since α < p-value, you cannot reject H0. Conclusion: There is not sufficient evidence to conclude that there is a difference among the mean grades for the sororities.
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In the bean plant test, how many total plants were grown?
- 15
- 5
- 3
- 12
Reveal answer
Answer: 15
Source evidence
PDF page 763: The dfs for the denominator = the total number of samples – the number of groups = 15 – 3 = 12
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For the bean plant test, the numerator degrees of freedom equaled:
- 3
- 2
- 12
- 15
Reveal answer
Answer: 2
Source evidence
PDF page 763: The dfs for the numerator = the number of groups – 1 = 3 – 1 = 2.
Introductory Statistics
Introductory Statistics by OpenStax, used under CC BY 4.0. Changes made by Stratacademy.
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