Hypergeometric Distribution Quiz
The question sheet
Reveal any answer as you study-
How many characteristics does a hypergeometric experiment have?
- Six
- Three
- Four
- Five
Reveal answer
Answer: Five
Source evidence
PDF page 271: There are five characteristics of a hypergeometric experiment.
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In the candy dish problem, what is the size of the sample?
- 100
- 50
- 35
- 80
Reveal answer
Answer: 50
Source evidence
PDF page 271: A candy dish contains 100 jelly beans and 80 gumdrops. Fifty candies are picked at random. What is the probability that 35 of the 50 are gumdrops? The two groups are jelly beans and gumdrops. Since the probability question asks for the probability of picking gumdrops, the group of interest (first group) is gumdrops. The size of the group of interest (first group) is 80. The size of the second group is 100. The size of the sample is 50 (jelly beans or gumdrops). Let X = the number of gumdrops in the sample of 50. X takes on the values x = 0, 1, 2, ...,
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In the candy dish problem, what is the size of the group of interest?
- 80
- 50
- 100
- 35
Reveal answer
Answer: 80
Source evidence
PDF page 271: A candy dish contains 100 jelly beans and 80 gumdrops. Fifty candies are picked at random. What is the probability that 35 of the 50 are gumdrops? The two groups are jelly beans and gumdrops. Since the probability question asks for the probability of picking gumdrops, the group of interest (first group) is gumdrops. The size of the group of interest (first group) is 80. The size of the second group is 100. The size of the sample is 50 (jelly beans or gumdrops). Let X = the number of gumdrops in the sample of 50. X takes on the values x = 0, 1, 2, ...,
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For the DVD player shipment, what is the group of interest?
- The 12 inspected players
- All 100 players
- The 90 non-defective players
- The 10 defective players
Reveal answer
Answer: The 10 defective players
Source evidence
PDF page 272: Suppose a shipment of 100 DVD players is known to have ten defective players. An inspector randomly chooses 12 for inspection. He is interested in determining the probability that, among the 12 players, at most two are defective. The two groups are the 90 non-defective DVD players and the 10 defective DVD players. The group of interest (first group) is the defective group because the probability question asks for the probability of at most two defective DVD players. The size of the sample is 12 DVD players. (They may be non-defective or defective.) Let X = the number of defective DVD players in the sample of 12. X takes on the values 0, 1, 2, ..., 10. X may not take on the values 11 or 12. The sample size is 12, but there are only 10 defective DVD players. Write the probability statement mathematically.
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In the DVD player problem, why can X not take on values 11 or 12?
- There are only 10 defective players
- The population is 100
- At most two are defective
- The sample size is only 12
Reveal answer
Answer: There are only 10 defective players
Source evidence
PDF page 272: Suppose a shipment of 100 DVD players is known to have ten defective players. An inspector randomly chooses 12 for inspection. He is interested in determining the probability that, among the 12 players, at most two are defective. The two groups are the 90 non-defective DVD players and the 10 defective DVD players. The group of interest (first group) is the defective group because the probability question asks for the probability of at most two defective DVD players. The size of the sample is 12 DVD players. (They may be non-defective or defective.) Let X = the number of defective DVD players in the sample of 12. X takes on the values 0, 1, 2, ..., 10. X may not take on the values 11 or 12. The sample size is 12, but there are only 10 defective DVD players. Write the probability statement mathematically.
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For the school site committee of six men and five women, what are r, b, and n?
- r=5, b=6, n=4
- r=4, b=6, n=5
- r=6, b=4, n=5
- r=6, b=5, n=4
Reveal answer
Answer: r=6, b=5, n=4
Source evidence
PDF page 273: A school site committee is to be chosen randomly from six men and five women. If the committee consists of four members chosen randomly, what is the probability that two of them are men? How many men do you expect to be on the committee? Let X = the number of men on the committee of four. The men are the group of interest (first group).
PDF page 273: X takes on the values 0, 1, 2, 3, 4, where r = 6, b = 5, and n = 4. X ~ H(6, 5, 4)
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For X ~ H(6, 5, 4), what is P(x = 2)?
- 0.4545
- 0.2180
- 0.5000
- 0.4500
Reveal answer
Answer: 0.4545
Source evidence
PDF page 273: Find P(x = 2). P(x = 2) = 0.4545 (calculator or computer)
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For the school site committee, how many men are expected to be on it?
- About 4
- About 3
- About 2
- About 5
Reveal answer
Answer: About 2
Source evidence
PDF page 274: The y-axis contains the probability of X, where X = the number of men on the committee. You would expect m = 2.18 (about two) men on the committee. (4)(6) nr
PDF page 274: = = 2.18 r + b 6 + 5
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According to the note, do the TI-83+ and TI-84 have hypergeometric functions?
- No, they do not
- Only the TI-84 does
- Only the TI-83+ does
- Yes, both do
Reveal answer
Answer: No, they do not
Source evidence
PDF page 273: NOTE Currently, the TI-83+ and TI-84 do not have hypergeometric probability functions. There are a number of computer packages, including Microsoft Excel, that do.
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For the sports team of 11 men and 13 women, how many players make up the team?
- Seven
- Ten
- Twenty-four
- Eleven
Reveal answer
Answer: Ten
Source evidence
PDF page 271: a combined group of 11 men and 13 women. The team consists of ten players.
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In the sports team example, the probability of the second pick depends on:
- The number of women only
- What happened in the first pick
- The size of the team
- Replacement of the picked player
Reveal answer
Answer: What happened in the first pick
Source evidence
PDF page 271: 13 10 11 picking a woman first is . The probability of picking a man second is if a woman was picked first. It is if 24 23 23 a man was picked first. The probability of the second pick depends on what happened in the first pick.
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The committee problem is hypergeometric because you choose from:
- Three groups
- One large group
- Two groups (men and women)
- A continuous distribution
Reveal answer
Answer: Two groups (men and women)
Source evidence
PDF page 272: You are president of an on-campus special events organization. You need a committee of seven students to plan a special birthday party for the president of the college. Your organization consists of 18 women and 15 men. You are interested in the number of men on your committee. If the members of the committee are randomly selected, what is the probability that your committee has more than four men? This is a hypergeometric problem because you are choosing your committee from two groups (men and women).
Introductory Statistics
Introductory Statistics by OpenStax, used under CC BY 4.0. Changes made by Stratacademy.
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