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Lab 2: Chi-Square Test of Independence Quiz

12 questions math Grades 9-12

The question sheet

Reveal any answer as you study
  1. What is the goal of the student in this Lab 2 exercise?

    • Estimate a population mean
    • Build a histogram of snacks
    • Evaluate a snack–gender relationship
    • Compare two sample variances
    Reveal answer

    Answer: Evaluate a snack–gender relationship

    Source evidence

    PDF page 673: • The student will evaluate if there is a significant relationship between favorite type of snack and gender.

  2. The lab conducts a hypothesis test to determine whether the factors are what?

    • Equal in mean
    • Independent
    • Uniform
    • Normally distributed
    Reveal answer

    Answer: Independent

    Source evidence

    PDF page 673: Conduct a hypothesis test to determine if the factors are independent:

  3. According to the note, why might you combine two food categories?

    • To increase degrees of freedom
    • To make the table symmetric
    • So each cell has expected value ≥ 5
    • To reduce the sample size
    Reveal answer

    Answer: So each cell has expected value ≥ 5

    Source evidence

    PDF page 673: total the results. NOTE You may need to combine two food categories so that each cell has an expected value of at least five.

  4. A contingency table displays sample values for how many factors?

    • Two
    • Three
    • One
    • Four
    Reveal answer

    Answer: Two

    Source evidence

    PDF page 675: contingency table a table that displays sample values for two different factors that may be dependent or contingent on each other; facilitates determining conditional probabilities

  5. What is the null hypothesis for a chi-square test of independence?

    • The two factors are dependent
    • The two factors are independent
    • The data are normal
    • The variances are equal
    Reveal answer

    Answer: The two factors are independent

    Source evidence

    PDF page 675: To assess whether two factors are independent, you can apply the test of independence that uses the chi-square distribution. The null hypothesis for this test states that the two factors are independent. The test compares observed values to expected values. The test is right-tailed. Each observation or cell category must have an expected value of at least five.

  6. The test of independence makes use of which structure?

    • A dot plot
    • A frequency polygon
    • A contingency table
    • A box plot
    Reveal answer

    Answer: A contingency table

    Source evidence

    PDF page 675: The goodness-of-fit test is typically used to determine if data fits a particular distribution. The test of independence makes use of a contingency table to determine the independence of two factors. The test for homogeneity determines whether two populations come from the same distribution, even if this distribution is unknown.

  7. A chi-square test of independence is described as which type of test?

    • Left-tailed
    • Two-tailed
    • Nondirectional
    • Right-tailed
    Reveal answer

    Answer: Right-tailed

    Source evidence

    PDF page 675: To assess whether two factors are independent, you can apply the test of independence that uses the chi-square distribution. The null hypothesis for this test states that the two factors are independent. The test compares observed values to expected values. The test is right-tailed. Each observation or cell category must have an expected value of at least five.

  8. How are the degrees of freedom found in a test of independence?

    • (columns–1)(rows–1)
    • columns × rows
    • n – 1
    • k – 1
    Reveal answer

    Answer: (columns–1)(rows–1)

    Source evidence

    PDF page 676: • The number of degrees of freedom is equal to (number

    PDF page 676: of columns–1)(number of rows–1). 2

  9. How is the expected number in a cell computed for a test of independence?

    • total surveyed / k
    • (row total)(column total)/total surveyed
    • column total × rows
    • row total + column total
    Reveal answer

    Answer: (row total)(column total)/total surveyed

    Source evidence

    PDF page 676: • If the null hypothesis is true, the expected number

    PDF page 676: (row total)(column total) E = . total surveyed

  10. The chi-square distribution curve is described as skewed in which direction?

    • To the right
    • Bimodal
    • Symmetric
    • To the left
    Reveal answer

    Answer: To the right

    Source evidence

    PDF page 675: The chi-square distribution is a useful tool for assessment in a series of problem categories. These problem categories include primarily (i) whether a data set fits a particular distribution, (ii) whether the distributions of two populations are the same, (iii) whether two events might be independent, and (iv) whether there is a different variability than expected within a population. An important parameter in a chi-square distribution is the degrees of freedom df in a given problem. The random variable in the chi-square distribution is the sum of squares of df standard normal variables, which must be independent. The key characteristics of the chi-square distribution also depend directly on the degrees of freedom. The chi-square distribution curve is skewed to the right, and its shape depends on the degrees of freedom df. For df > 90, the curve approximates the normal distribution. Test statistics based on the chi-square distribution are always greater than or equal to zero. Such application tests are almost always right-tailed tests.

  11. For which df does the chi-square curve approximate the normal distribution?

    • df = 30
    • df > 90
    • df < 5
    • df = 1
    Reveal answer

    Answer: df > 90

    Source evidence

    PDF page 675: The chi-square distribution is a useful tool for assessment in a series of problem categories. These problem categories include primarily (i) whether a data set fits a particular distribution, (ii) whether the distributions of two populations are the same, (iii) whether two events might be independent, and (iv) whether there is a different variability than expected within a population. An important parameter in a chi-square distribution is the degrees of freedom df in a given problem. The random variable in the chi-square distribution is the sum of squares of df standard normal variables, which must be independent. The key characteristics of the chi-square distribution also depend directly on the degrees of freedom. The chi-square distribution curve is skewed to the right, and its shape depends on the degrees of freedom df. For df > 90, the curve approximates the normal distribution. Test statistics based on the chi-square distribution are always greater than or equal to zero. Such application tests are almost always right-tailed tests.

    PDF page 695: 3 when the number of degrees of freedom is greater than 90 5 df = 2 7 a goodness-of-fit test 9 3 11 2.04

  12. The Transit Railroads study asks whether ticket class choice is independent of what?

    • Time of day
    • Passenger age
    • Travel distance
    • Ticket price
    Reveal answer

    Answer: Travel distance

    Source evidence

    PDF page 679: Use the following information to answer the next seven exercises: Transit Railroads is interested in the relationship between travel distance and the ticket class purchased. A random sample of 200 passengers is taken. Table 11.31 shows the results. The railroad wants to know if a passenger’s choice in ticket class is independent of the distance the passenger must travel.

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