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Lab 2: Chi-Square Test of Independence Quiz

12 questions math Grades 9-12

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  1. In the test of independence, what does the null hypothesis state?

    • The variance equals expected
    • The two factors are dependent
    • The two factors are independent
    • The data fits a distribution
    Reveal answer

    Answer: The two factors are independent

    Source evidence

    PDF page 659: To assess whether two factors are independent or not, you can apply the test of independence that uses the chi-square distribution. The null hypothesis for this test states that the two factors are independent. The test compares observed values to expected values. The test is right-tailed. Each observation or cell category must have an expected value of at least 5.

  2. For the test of independence, what tail is used?

    • Neither tail
    • Two-tailed
    • Right-tailed
    • Left-tailed
    Reveal answer

    Answer: Right-tailed

    Source evidence

    PDF page 659: To assess whether two factors are independent or not, you can apply the test of independence that uses the chi-square distribution. The null hypothesis for this test states that the two factors are independent. The test compares observed values to expected values. The test is right-tailed. Each observation or cell category must have an expected value of at least 5.

  3. What is the minimum expected value each cell must have in the test of independence?

    • 3
    • 1
    • 10
    • 5
    Reveal answer

    Answer: 5

    Source evidence

    PDF page 659: To assess whether two factors are independent or not, you can apply the test of independence that uses the chi-square distribution. The null hypothesis for this test states that the two factors are independent. The test compares observed values to expected values. The test is right-tailed. Each observation or cell category must have an expected value of at least 5.

  4. What kind of table does the test of independence use?

    • Contingency table
    • Probability table
    • Frequency table
    • Z-table
    Reveal answer

    Answer: Contingency table

    Source evidence

    PDF page 659: The goodness-of-fit test is typically used to determine if data fits a particular distribution. The test of independence makes use of a contingency table to determine the independence of two factors. The test for homogeneity determines whether two populations come from the same distribution, even if this distribution is unknown.

  5. What is a contingency table?

    • A single-column frequency chart
    • A random number table
    • A list of z-scores
    • A table of two factors that may depend
    Reveal answer

    Answer: A table of two factors that may depend

    Source evidence

    PDF page 659: Contingency Table a table that displays sample values for two different factors that may be dependent or contingent on one another; it facilitates determining conditional probabilities.

  6. For the test of independence, degrees of freedom equal:

    • number of cells - 1
    • rows + columns
    • sample size - 1
    • (rows - 1)(columns - 1)
    Reveal answer

    Answer: (rows - 1)(columns - 1)

    Source evidence

    PDF page 660: • The number of degrees of freedom is equal to (number

    PDF page 660: of columns - 1)(number of rows - 1). 2

  7. How is the expected value for a cell calculated?

    • observed minus expected
    • row total + column total
    • (row total)(column total)/total surveyed
    • total surveyed / cells
    Reveal answer

    Answer: (row total)(column total)/total surveyed

    Source evidence

    PDF page 660: (row total)(column total) E = . total surveyed

  8. The chi-square distribution curve is described as:

    • Skewed to the left
    • Symmetric and bell-shaped
    • Uniform
    • Skewed to the right
    Reveal answer

    Answer: Skewed to the right

    Source evidence

    PDF page 659: The chi-square distribution is a useful tool for assessment in a series of problem categories. These problem categories include primarily (i) whether a data set fits a particular distribution, (ii) whether the distributions of two populations are the same, (iii) whether two events might be independent, and (iv) whether there is a different variability than expected within a population. An important parameter in a chi-square distribution is the degrees of freedom df in a given problem. The random variable in the chi-square distribution is the sum of squares of df standard normal variables, which must be independent. The key characteristics of the chi-square distribution also depend directly on the degrees of freedom. The chi-square distribution curve is skewed to the right, and its shape depends on the degrees of freedom df. For df > 90, the curve approximates the normal distribution. Test statistics based on the chi-square distribution are always greater than or equal to zero. Such application tests are almost always right-tailed tests.

  9. Test statistics based on the chi-square distribution are always:

    • Equal to the mean
    • Between -1 and 1
    • Greater than or equal to zero
    • Less than zero
    Reveal answer

    Answer: Greater than or equal to zero

    Source evidence

    PDF page 659: The chi-square distribution is a useful tool for assessment in a series of problem categories. These problem categories include primarily (i) whether a data set fits a particular distribution, (ii) whether the distributions of two populations are the same, (iii) whether two events might be independent, and (iv) whether there is a different variability than expected within a population. An important parameter in a chi-square distribution is the degrees of freedom df in a given problem. The random variable in the chi-square distribution is the sum of squares of df standard normal variables, which must be independent. The key characteristics of the chi-square distribution also depend directly on the degrees of freedom. The chi-square distribution curve is skewed to the right, and its shape depends on the degrees of freedom df. For df > 90, the curve approximates the normal distribution. Test statistics based on the chi-square distribution are always greater than or equal to zero. Such application tests are almost always right-tailed tests.

  10. For what df does the chi-square curve approximate the normal distribution?

    • df > 30
    • df = 2
    • df > 90
    • df < 10
    Reveal answer

    Answer: df > 90

    Source evidence

    PDF page 659: The chi-square distribution is a useful tool for assessment in a series of problem categories. These problem categories include primarily (i) whether a data set fits a particular distribution, (ii) whether the distributions of two populations are the same, (iii) whether two events might be independent, and (iv) whether there is a different variability than expected within a population. An important parameter in a chi-square distribution is the degrees of freedom df in a given problem. The random variable in the chi-square distribution is the sum of squares of df standard normal variables, which must be independent. The key characteristics of the chi-square distribution also depend directly on the degrees of freedom. The chi-square distribution curve is skewed to the right, and its shape depends on the degrees of freedom df. For df > 90, the curve approximates the normal distribution. Test statistics based on the chi-square distribution are always greater than or equal to zero. Such application tests are almost always right-tailed tests.

  11. A study on age and symptoms in 500 infected people uses which test?

    • A test of independence
    • A test for homogeneity
    • A test of a single variance
    • A goodness-of-fit test
    Reveal answer

    Answer: A test of independence

    Source evidence

    PDF page 663: 23. A pharmaceutical company is interested in the relationship between age and presentation of symptoms for a common

    PDF page 663: viral infection. A random sample is taken of 500 people with the infection across different age groups.

    PDF page 679: Conclusion (write out in complete sentences): The make-up of AIDS cases does not fit the ethnicities of the general population of Santa Clara County. 23 a test of independence 25 a test of independence 27 8 29 6.6 31 0.0435 33

  12. In the smoking-by-ethnicity test, what was the decision at α = 0.05?

    • Accept the alternative fully
    • Do not reject the null
    • Reject the null hypothesis
    • Fail to test
    Reveal answer

    Answer: Reject the null hypothesis

    Source evidence

    PDF page 680: a. Reject the null hypothesis.

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