Matched or Paired Samples (Optional) Quiz
The question sheet
Reveal any answer as you study-
In a matched or paired samples test, subjects are matched in pairs and what is calculated?
- The ratios
- The differences
- The products
- The sums
Reveal answer
Answer: The differences
Source evidence
PDF page 608: sufficiently large so that distribution of the sample mean of differences is approximately normal. In a hypothesis test for matched or paired samples, subjects are matched in pairs and differences are calculated. The differences are the data. The population mean for the differences, μd, is then tested using a Student’s-t test for a single population mean with n – 1 degrees of freedom, where n is the number of differences. The test statistic (t-score) is ̄ x − μ
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In a matched or paired samples test, what serves as the data?
- The after values
- The averages
- The differences
- The before values
Reveal answer
Answer: The differences
Source evidence
PDF page 608: sufficiently large so that distribution of the sample mean of differences is approximately normal. In a hypothesis test for matched or paired samples, subjects are matched in pairs and differences are calculated. The differences are the data. The population mean for the differences, μd, is then tested using a Student’s-t test for a single population mean with n – 1 degrees of freedom, where n is the number of differences. The test statistic (t-score) is ̄ x − μ
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The population mean for the differences in a paired test is denoted by which symbol?
- pd
- μd
- x̄d
- σd
Reveal answer
Answer: μd
Source evidence
PDF page 608: sufficiently large so that distribution of the sample mean of differences is approximately normal. In a hypothesis test for matched or paired samples, subjects are matched in pairs and differences are calculated. The differences are the data. The population mean for the differences, μd, is then tested using a Student’s-t test for a single population mean with n – 1 degrees of freedom, where n is the number of differences. The test statistic (t-score) is ̄ x − μ
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A matched or paired samples test uses a Student's-t test with how many degrees of freedom?
- 2n
- n + 1
- n
- n – 1
Reveal answer
Answer: n – 1
Source evidence
PDF page 608: sufficiently large so that distribution of the sample mean of differences is approximately normal. In a hypothesis test for matched or paired samples, subjects are matched in pairs and differences are calculated. The differences are the data. The population mean for the differences, μd, is then tested using a Student’s-t test for a single population mean with n – 1 degrees of freedom, where n is the number of differences. The test statistic (t-score) is ̄ x − μ
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In the paired test, n represents the number of what?
- Differences
- Subjects total
- Populations
- Trials
Reveal answer
Answer: Differences
Source evidence
PDF page 608: sufficiently large so that distribution of the sample mean of differences is approximately normal. In a hypothesis test for matched or paired samples, subjects are matched in pairs and differences are calculated. The differences are the data. The population mean for the differences, μd, is then tested using a Student’s-t test for a single population mean with n – 1 degrees of freedom, where n is the number of differences. The test statistic (t-score) is ̄ x − μ
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In the pain medication study, the differences were tested at what significance level?
- 5 percent
- 1 percent
- 2 percent
- 10 percent
Reveal answer
Answer: 5 percent
Source evidence
PDF page 608: A study was conducted to investigate the effectiveness of pain-reducing medication. Results for randomly selected subjects are shown in Table 10.10. A lower score indicates less pain. The before value is matched to an after value, and the differences are calculated. The differences have a normal distribution. Are the sensory measurements, on average, lower after the medication? Test at a 5 percent significance level.
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In the pain study, what does a lower score indicate?
- No change
- Higher stress
- Less pain
- More pain
Reveal answer
Answer: Less pain
Source evidence
PDF page 608: A study was conducted to investigate the effectiveness of pain-reducing medication. Results for randomly selected subjects are shown in Table 10.10. A lower score indicates less pain. The before value is matched to an after value, and the differences are calculated. The differences have a normal distribution. Are the sensory measurements, on average, lower after the medication? Test at a 5 percent significance level.
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For the pain study, the differences were calculated as which operation?
- After × before
- After – before
- Before – after
- After + before
Reveal answer
Answer: After – before
Source evidence
PDF page 609: Solution 10.11 Corresponding before and after values form matched pairs. (Calculate after – before.)
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For the pain study differences, what was the sample mean x̄d?
- 3.13
- 2.91
- –2.91
- –3.13
Reveal answer
Answer: –3.13
Source evidence
PDF page 609: The data for the test are the differences: {0.2, –4.1, –1.6, –1.8, –3.2, –2, –2.9, –9.6} The sample mean and sample standard deviation of the differences are: x = –3.13 and s = 2.91 d d Verify these values. Let μ be the population mean for the differences. We use the subscript d to denote differences. d
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For the pain study differences, what was the sample standard deviation sd?
- 9.6
- 3.13
- 0.2
- 2.91
Reveal answer
Answer: 2.91
Source evidence
PDF page 609: The data for the test are the differences: {0.2, –4.1, –1.6, –1.8, –3.2, –2, –2.9, –9.6} The sample mean and sample standard deviation of the differences are: x = –3.13 and s = 2.91 d d Verify these values. Let μ be the population mean for the differences. We use the subscript d to denote differences. d
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In the pain study, what is the random variable X̄d?
- Total pain score
- Mean difference of measurements
- Standard deviation of scores
- Population size
Reveal answer
Answer: Mean difference of measurements
Source evidence
PDF page 609: ̄ Random variable: X = the mean difference of the sensory measurements. d
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In the pain study, what was the alternative hypothesis Ha?
- μd > 0
- μd ≠ 0
- μd < 0
- μd = 0
Reveal answer
Answer: μd < 0
Source evidence
PDF page 609: The null hypothesis is zero or positive, meaning that there is the same or more pain felt after taking the medication. That means the subject shows no improvement. μd is the population mean of the differences. Ha: μd < 0 The alternative hypothesis is negative, meaning there is less pain felt after taking the medication. That means the subject shows improvement. The score should be lower after taking the medication, so the difference ought to be negative to indicate improvement.
High School Statistics
High School Statistics by OpenStax, used under CC BY 4.0. Changes made by Stratacademy.
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