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The Central Limit Theorem for Sample Means (Averages) Quiz

12 questions math Grades 9-12

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  1. According to the central limit theorem, as sample size n increases, the sample means tend to be distributed how?

    • Normally
    • Exponentially
    • Skewed right
    • Uniformly
    Reveal answer

    Answer: Normally

    Source evidence

    PDF page 423: ̄ If you draw random samples of size n, then as n increases, the random variable X , which consists of sample means, tends to be normally distributed and ̄

    PDF page 423: ⎛ σ ⎞ x X ∼ N μx, ⎝ n⎠ The central limit theorem for sample means says that if you keep drawing larger and larger samples (such as rolling one, two, five, and finally, ten dice) and calculating their means, the sample means form their own normal distribution (the sampling distribution). The normal distribution has the same mean as the original distribution and a variance that equals the original variance divided by the sample size. The variable n is the number of values that are averaged together, not the number of times the experiment is done. ̄ To put it more formally, if you draw random samples of size n, the distribution of the random variable X , which consists of sample means, is called the sampling distribution of the mean. The sampling distribution of the mean approaches a normal distribution as n, the sample size, increases. ̄ ̄ The random variable X has a different z-score associated with it from that of the random variable X. The mean x is the ̄ value of X in one sample. ̄ x − μx z = ,

  2. In the central limit theorem, what does the variable n represent?

    • Number of standard deviations
    • Total population size
    • Times the experiment is done
    • Number of values averaged together
    Reveal answer

    Answer: Number of values averaged together

    Source evidence

    PDF page 423: ⎛ σ ⎞ x X ∼ N μx, ⎝ n⎠ The central limit theorem for sample means says that if you keep drawing larger and larger samples (such as rolling one, two, five, and finally, ten dice) and calculating their means, the sample means form their own normal distribution (the sampling distribution). The normal distribution has the same mean as the original distribution and a variance that equals the original variance divided by the sample size. The variable n is the number of values that are averaged together, not the number of times the experiment is done. ̄ To put it more formally, if you draw random samples of size n, the distribution of the random variable X , which consists of sample means, is called the sampling distribution of the mean. The sampling distribution of the mean approaches a normal distribution as n, the sample size, increases. ̄ ̄ The random variable X has a different z-score associated with it from that of the random variable X. The mean x is the ̄ value of X in one sample. ̄ x − μx z = ,

  3. The sampling distribution of the mean has the same mean as which distribution?

    • The original distribution
    • A uniform distribution
    • A larger distribution
    • The z-score distribution
    Reveal answer

    Answer: The original distribution

    Source evidence

    PDF page 423: ⎛ σ ⎞ x X ∼ N μx, ⎝ n⎠ The central limit theorem for sample means says that if you keep drawing larger and larger samples (such as rolling one, two, five, and finally, ten dice) and calculating their means, the sample means form their own normal distribution (the sampling distribution). The normal distribution has the same mean as the original distribution and a variance that equals the original variance divided by the sample size. The variable n is the number of values that are averaged together, not the number of times the experiment is done. ̄ To put it more formally, if you draw random samples of size n, the distribution of the random variable X , which consists of sample means, is called the sampling distribution of the mean. The sampling distribution of the mean approaches a normal distribution as n, the sample size, increases. ̄ ̄ The random variable X has a different z-score associated with it from that of the random variable X. The mean x is the ̄ value of X in one sample. ̄ x − μx z = ,

  4. The variance of the sampling distribution equals the original variance divided by what?

    • The standard deviation
    • The mean
    • The sample size
    • Two
    Reveal answer

    Answer: The sample size

    Source evidence

    PDF page 423: ⎛ σ ⎞ x X ∼ N μx, ⎝ n⎠ The central limit theorem for sample means says that if you keep drawing larger and larger samples (such as rolling one, two, five, and finally, ten dice) and calculating their means, the sample means form their own normal distribution (the sampling distribution). The normal distribution has the same mean as the original distribution and a variance that equals the original variance divided by the sample size. The variable n is the number of values that are averaged together, not the number of times the experiment is done. ̄ To put it more formally, if you draw random samples of size n, the distribution of the random variable X , which consists of sample means, is called the sampling distribution of the mean. The sampling distribution of the mean approaches a normal distribution as n, the sample size, increases. ̄ ̄ The random variable X has a different z-score associated with it from that of the random variable X. The mean x is the ̄ value of X in one sample. ̄ x − μx z = ,

  5. For a distribution with mean 90, σ=15, n=25, what is the standard error of the mean?

    • 5
    • 90
    • 15
    • 3
    Reveal answer

    Answer: 3

    Source evidence

    PDF page 424: ⎝ n⎠ ⎛ 15 ⎞ value = 90 + 2 = 96. ⎝ 25⎠ The value that is two standard deviations above the expected value is 96. 15 σx The standard error of the mean is = = 3. Recall that the standard error of the mean is a description of n 25 how far (on average) that the sample mean will be from the population mean in repeated simple random samples of size n.

  6. With mean 90, σ=15, n=25, what is P(85 < x̄ < 92)?

    • 0.6997
    • 0.5000
    • 0.9962
    • 0.9977
    Reveal answer

    Answer: 0.6997

    Source evidence

    PDF page 424: ⎛ σ ⎞ x X ∼ N μx, ⎝ n⎠ ̄ Find P(85 < x < 92). Draw a graph. ̄ P(85 < x < 92) = 0.6997 The probability that the sample mean is between 85 and 92 is 0.6997.

    PDF page 424: ̄ Find P(85 < x < 92). Draw a graph. ̄ P(85 < x < 92) = 0.6997

  7. What value is two standard deviations above the expected value 90 of the sample mean (σ=15, n=25)?

    • 93
    • 96
    • 99
    • 120
    Reveal answer

    Answer: 96

    Source evidence

    PDF page 424: b. Find the value that is two standard deviations above the expected value, 90, of the sample mean.

    PDF page 424: ⎝ n⎠ ⎛ 15 ⎞ value = 90 + 2 = 96. ⎝ 25⎠ The value that is two standard deviations above the expected value is 96. 15 σx The standard error of the mean is = = 3. Recall that the standard error of the mean is a description of n 25 how far (on average) that the sample mean will be from the population mean in repeated simple random samples of size n.

  8. For the soccer match example (μ=2, σ=0.5, n=50), what is P(1.8 < x̄ < 2.3)?

    • 0.9977
    • 0.9962
    • 0.9293
    • 0.6997
    Reveal answer

    Answer: 0.9977

    Source evidence

    PDF page 425: ⎝ 50⎠ ̄ Find P(1.8 < x < 2.3). Draw a graph. ̄ P(1.8 < x < 2.3) = 0.9977 normalcdf ⎛ .5 ⎞ 1.8,2.3,2, = 0.9977 ⎝ 50⎠ The probability that the mean time is between 1.8 hours and 2.3 hours is 0.9977.

  9. For tablet users (μ=34, σ=15, n=100), what is the mean of the sample mean ages?

    • 15
    • 34
    • 30
    • 1.5
    Reveal answer

    Answer: 34

    Source evidence

    PDF page 426: a. Because the sample mean tends to target the population mean, we have μχ = μ = 34. The sample standard

  10. For tablet users (μ=34, σ=15, n=100), what is the 95th percentile for the sample mean age?

    • 38.2
    • 30.0
    • 36.5
    • 34.0
    Reveal answer

    Answer: 36.5

    Source evidence

    PDF page 426: d. Let k = the 95 percentile.

    PDF page 426: ⎛ 15 ⎞ k = invNorm 0.95,34, = 36.5 ⎝ 100⎠

  11. According to the CLT, for large sample sizes the sampling distribution will be approximately what?

    • Bimodal
    • Uniform
    • Exponential
    • Normal
    Reveal answer

    Answer: Normal

    Source evidence

    PDF page 426: b. The central limit theorem states that for large sample sizes (n), the sampling distribution will be

    PDF page 426: approximately normal.

  12. For app engagement (μ=8.2, σ=1, n=60), what is the standard error of the mean?

    • 8.2
    • 1.0
    • 0.13
    • 0.90
    Reveal answer

    Answer: 0.13

    Source evidence

    PDF page 427: Solution 7.4 σ 1 = 0.13

    PDF page 427: a. μ ̄ = μ = 8.2 σ ̄ = =

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