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Two Basic Rules of Probability Quiz

12 questions math Grades 9-12

The question sheet

Reveal any answer as you study
  1. According to the multiplication rule, P(A AND B) equals:

    • P(A) − P(B)
    • P(A)/P(B)
    • P(A) + P(B)
    • P(B)P(A|B)
    Reveal answer

    Answer: P(B)P(A|B)

    Source evidence

    PDF page 197: If A and B are two events defined on a sample space, then: P(A AND B) = P(B)P(A|B). P(A AND B) This rule may also be written as: P(A|B) = P(B) (The probability of A given B equals the probability of A and B divided by the probability of B.)

  2. If A and B are independent, then P(A|B) equals:

    • 1
    • 0
    • P(A)
    • P(B)
    Reveal answer

    Answer: P(A)

    Source evidence

    PDF page 197: If A and B are independent, then P(A|B) = P(A). Then P(A AND B) = P(A|B)P(B) becomes P(A AND B) = P(A)P(B).

  3. For independent events A and B, P(A AND B) becomes:

    • P(A)P(B)
    • 0
    • P(A) + P(B)
    • P(A) − P(B)
    Reveal answer

    Answer: P(A)P(B)

    Source evidence

    PDF page 197: If A and B are independent, then P(A|B) = P(A). Then P(A AND B) = P(A|B)P(B) becomes P(A AND B) = P(A)P(B).

  4. If A and B are mutually exclusive, then P(A AND B) equals:

    • 0
    • P(A)P(B)
    • 1
    • 0.5
    Reveal answer

    Answer: 0

    Source evidence

    PDF page 197: If A and B are defined on a sample space, then: P(A OR B) = P(A) + P(B) - P(A AND B). If A and B are mutually exclusive, then P(A AND B) = 0. Then P(A OR B) = P(A) + P(B) - P(A AND B) becomes P(A OR

  5. For Klaus, P(A)=0.6 and P(B)=0.35 with P(A AND B)=0. What is P(A OR B)?

    • 1.0
    • 0.21
    • 0.95
    • 0.05
    Reveal answer

    Answer: 0.95

    Source evidence

    PDF page 197: • Therefore, the probability that he chooses either New Zealand or Alaska is P(A OR B) = P(A) + P(B) = 0.6

    PDF page 197: + 0.35 = 0.95. Note that the probability that he does not choose to go anywhere on vacation must be 0.05.

  6. Why is P(A AND B)=0 in the Klaus vacation problem?

    • The trips cost the same
    • He dislikes both trips
    • He can only afford one vacation
    • Both trips are identical
    Reveal answer

    Answer: He can only afford one vacation

    Source evidence

    PDF page 197: • P(A AND B) = 0 because Klaus can only afford to take one vacation

  7. Carlos: P(A)=0.65 and P(B|A)=0.90. What is P(A AND B)?

    • 0.715
    • 0.90
    • 0.585
    • 0.423
    Reveal answer

    Answer: 0.585

    Source evidence

    PDF page 197: a. The problem is asking you to find P(A AND B) = P(B AND A). Since P(B|A) = 0.90: P(B AND A) = P(B|A)

    PDF page 197: P(A) = (0.90)(0.65) = 0.585

  8. For Carlos, what is P(A OR B) if P(A AND B)=0.585?

    • 0.715
    • 0.65
    • 1.30
    • 0.585
    Reveal answer

    Answer: 0.715

    Source evidence

    PDF page 197: P(A OR B) = P(A) + P(B) - P(A AND B) = 0.65 + 0.65 - 0.585 = 0.715

  9. Are Carlos's events A and B independent?

    • Yes, because P(A)=P(B)
    • Yes, they never overlap
    • Cannot be determined
    • No, P(B AND A)≠P(B)P(A)
    Reveal answer

    Answer: No, P(B AND A)≠P(B)P(A)

    Source evidence

    PDF page 197: c. No, they are not, because P(B AND A) = 0.585.

    PDF page 198: 0.423 ≠ 0.585 = P(B AND A)

    PDF page 198: So, P(B AND A) is not equal to P(B)P(A).

  10. For Carlos, P(B)P(A)=(0.65)(0.65) equals:

    • 0.130
    • 0.715
    • 0.585
    • 0.423
    Reveal answer

    Answer: 0.423

    Source evidence

    PDF page 198: P(B)P(A) = (0.65)(0.65) = 0.423

  11. To be mutually exclusive, P(A AND B) must equal:

    • one
    • 0.585
    • P(A)P(B)
    • zero
    Reveal answer

    Answer: zero

    Source evidence

    PDF page 198: To be mutually exclusive, P(A AND B) must equal zero.

  12. In the swim team of 150, what is P(novice swimmer)?

    • 75/150
    • 80/150
    • 28/150
    • 40/150
    Reveal answer

    Answer: 28/150

    Source evidence

    PDF page 198: Solution 3.16 28 a. 150

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