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Applications of Thermodynamics: Heat Engines, Heat Pumps, and Refrigerators Quiz

12 questions physics Grades 9-12

The question sheet

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  1. Which of these is an example of a heat engine?

    • A heat pump
    • An air conditioner
    • A refrigerator
    • A jet engine
    Reveal answer

    Answer: A jet engine

    Source evidence

    PDF page 386: In this section, we’ll explore how heat engines, heat pumps, and refrigerators operate in terms of the laws of thermodynamics. One of the most important things we can do with heat is to use it to do work for us. A heat engine does exactly this—it makes use of the properties of thermodynamics to transform heat into work. Gasoline and diesel engines, jet engines, and steam turbines that generate electricity are all examples of heat engines.

  2. What process brings a system back to its original state at the end of every cycle?

    • Adiabatic process
    • Isothermal process
    • Reversible process
    • Cyclical process
    Reveal answer

    Answer: Cyclical process

    Source evidence

    PDF page 387: To repeat this process, the piston needs to be returned to its starting point. Heat now transfers energy from the gas to the surroundings, so that the gas’s pressure decreases, and a force is exerted by the surroundings to push the piston back through some distance. A cyclical process brings a system, such as the gas in a cylinder, back to its original state at the end of every cycle. All heat engines use cyclical processes. Heat engines do work by using part of the energy transferred by heat from some source. As shown in Figure 12.14, heat transfers

    PDF page 392: J/K, which is used in the ideal gas law cyclical process process in which a system is brought back to its original state at the end of every cycle entropy measurement of a system's disorder and how much energy is not available to do work in a system first law of thermodynamics states that the change in internal energy of a system equals the net energy transfer by heat into the system minus the net work done by the system heat engine machine that uses energy transfer by heat to do work heat pump machine that generates the heat transfer of energy from cold to hot ideal gas law physical law that relates the pressure and volume of a gas to the number of gas molecules or atoms, or number of moles of gas, and the absolute temperature

  3. All heat engines use what type of process?

    • Linear process
    • Cyclical process
    • Static process
    • One-way process
    Reveal answer

    Answer: Cyclical process

    Source evidence

    PDF page 387: To repeat this process, the piston needs to be returned to its starting point. Heat now transfers energy from the gas to the surroundings, so that the gas’s pressure decreases, and a force is exerted by the surroundings to push the piston back through some distance. A cyclical process brings a system, such as the gas in a cylinder, back to its original state at the end of every cycle. All heat engines use cyclical processes. Heat engines do work by using part of the energy transferred by heat from some source. As shown in Figure 12.14, heat transfers

  4. In physics, a reservoir is defined as an infinitely large mass that can do what?

    • Emit light continuously
    • Convert entropy into work
    • Store only work, not heat
    • Take in or put out unlimited heat
    Reveal answer

    Answer: Take in or put out unlimited heat

    Source evidence

    PDF page 387: temperature object (or cold reservoir), and the work done by the engine is W. In physics, a reservoir is defined as an infinitely large mass that can take in or put out an unlimited amount of heat, depending upon the needs of the system. The temperature of the hot reservoir is and the temperature of the cold reservoir is .

  5. In a heat engine, from which reservoir is energy transferred by heat first?

    • External sink
    • Neutral reservoir
    • Cold reservoir
    • Hot reservoir
    Reveal answer

    Answer: Hot reservoir

    Source evidence

    PDF page 387: energy, , from the high-temperature object (or hot reservoir), whereas heat transfers unused energy, , into the low-

    PDF page 388: thermodynamics. (b) A heat engine, represented here by a circle, uses part of the energy transferred by heat to do work. The hot and cold objects are called the hot and cold reservoirs. Qh is the heat out of the hot reservoir, W is the work output, and Qc is the unused heat into the cold reservoir.

  6. For a complete cycle in a heat engine, the change in internal energy is:

    • Negative
    • Positive
    • Maximum
    • Zero
    Reveal answer

    Answer: Zero

    Source evidence

    PDF page 388: As noted, a cyclical process brings the system back to its original condition at the end of every cycle. Such a system’s internal energy, U, is the same at the beginning and end of every cycle—that is, . The first law of thermodynamics states that where Q is the net heat transfer during the cycle, and W is the net work done by the system. The net heat transfer is the energy transferred in by heat from the hot reservoir minus the amount that is transferred out to the cold reservoir ). Because there is no change in internal energy for a complete cycle ( ), we have ( 12.19 so that 12.20 Therefore, the net work done by the system equals the net heat into the system, or 12.21 for a cyclical process. Because the hot reservoir is heated externally, which is an energy-intensive process, it is important that the work be done as efficiently as possible. In fact, we want W to equal , and for there to be no heat to the environment (that is, ). Unfortunately, this is impossible. According to the second law of thermodynamics, heat engines cannot have perfect conversion of heat into work. Recall that entropy is a measure of the disorder of a system, which is also how much energy is unavailable to do work. The second law of thermodynamics requires that the total entropy of a system either increases or remains constant in any process. Therefore, there is a minimum amount of that cannot be used for work. The amount of heat rejected to the cold reservoir, depends upon the efficiency of the heat engine. The smaller the increase in entropy, , the smaller the value of , and the more heat energy is available to do work. Heat pumps, air conditioners, and refrigerators utilize heat transfer of energy from low to high temperatures, which is the

  7. For a cyclical process, the net work done by the system equals what?

    • The entropy of the cold reservoir
    • The net heat into the system
    • The internal energy change
    • Twice the input heat
    Reveal answer

    Answer: The net heat into the system

    Source evidence

    PDF page 388: As noted, a cyclical process brings the system back to its original condition at the end of every cycle. Such a system’s internal energy, U, is the same at the beginning and end of every cycle—that is, . The first law of thermodynamics states that where Q is the net heat transfer during the cycle, and W is the net work done by the system. The net heat transfer is the energy transferred in by heat from the hot reservoir minus the amount that is transferred out to the cold reservoir ). Because there is no change in internal energy for a complete cycle ( ), we have ( 12.19 so that 12.20 Therefore, the net work done by the system equals the net heat into the system, or 12.21 for a cyclical process. Because the hot reservoir is heated externally, which is an energy-intensive process, it is important that the work be done as efficiently as possible. In fact, we want W to equal , and for there to be no heat to the environment (that is, ). Unfortunately, this is impossible. According to the second law of thermodynamics, heat engines cannot have perfect conversion of heat into work. Recall that entropy is a measure of the disorder of a system, which is also how much energy is unavailable to do work. The second law of thermodynamics requires that the total entropy of a system either increases or remains constant in any process. Therefore, there is a minimum amount of that cannot be used for work. The amount of heat rejected to the cold reservoir, depends upon the efficiency of the heat engine. The smaller the increase in entropy, , the smaller the value of , and the more heat energy is available to do work. Heat pumps, air conditioners, and refrigerators utilize heat transfer of energy from low to high temperatures, which is the

  8. According to the second law of thermodynamics, heat engines cannot:

    • Operate cyclically
    • Do any useful work
    • Use a hot reservoir
    • Perfectly convert heat into work
    Reveal answer

    Answer: Perfectly convert heat into work

    Source evidence

    PDF page 388: As noted, a cyclical process brings the system back to its original condition at the end of every cycle. Such a system’s internal energy, U, is the same at the beginning and end of every cycle—that is, . The first law of thermodynamics states that where Q is the net heat transfer during the cycle, and W is the net work done by the system. The net heat transfer is the energy transferred in by heat from the hot reservoir minus the amount that is transferred out to the cold reservoir ). Because there is no change in internal energy for a complete cycle ( ), we have ( 12.19 so that 12.20 Therefore, the net work done by the system equals the net heat into the system, or 12.21 for a cyclical process. Because the hot reservoir is heated externally, which is an energy-intensive process, it is important that the work be done as efficiently as possible. In fact, we want W to equal , and for there to be no heat to the environment (that is, ). Unfortunately, this is impossible. According to the second law of thermodynamics, heat engines cannot have perfect conversion of heat into work. Recall that entropy is a measure of the disorder of a system, which is also how much energy is unavailable to do work. The second law of thermodynamics requires that the total entropy of a system either increases or remains constant in any process. Therefore, there is a minimum amount of that cannot be used for work. The amount of heat rejected to the cold reservoir, depends upon the efficiency of the heat engine. The smaller the increase in entropy, , the smaller the value of , and the more heat energy is available to do work. Heat pumps, air conditioners, and refrigerators utilize heat transfer of energy from low to high temperatures, which is the

  9. Entropy is a measure of a system's disorder and how much energy is:

    • Not available to do work
    • Available to do work
    • Stored as mass
    • Lost to friction only
    Reveal answer

    Answer: Not available to do work

    Source evidence

    PDF page 388: As noted, a cyclical process brings the system back to its original condition at the end of every cycle. Such a system’s internal energy, U, is the same at the beginning and end of every cycle—that is, . The first law of thermodynamics states that where Q is the net heat transfer during the cycle, and W is the net work done by the system. The net heat transfer is the energy transferred in by heat from the hot reservoir minus the amount that is transferred out to the cold reservoir ). Because there is no change in internal energy for a complete cycle ( ), we have ( 12.19 so that 12.20 Therefore, the net work done by the system equals the net heat into the system, or 12.21 for a cyclical process. Because the hot reservoir is heated externally, which is an energy-intensive process, it is important that the work be done as efficiently as possible. In fact, we want W to equal , and for there to be no heat to the environment (that is, ). Unfortunately, this is impossible. According to the second law of thermodynamics, heat engines cannot have perfect conversion of heat into work. Recall that entropy is a measure of the disorder of a system, which is also how much energy is unavailable to do work. The second law of thermodynamics requires that the total entropy of a system either increases or remains constant in any process. Therefore, there is a minimum amount of that cannot be used for work. The amount of heat rejected to the cold reservoir, depends upon the efficiency of the heat engine. The smaller the increase in entropy, , the smaller the value of , and the more heat energy is available to do work. Heat pumps, air conditioners, and refrigerators utilize heat transfer of energy from low to high temperatures, which is the

    PDF page 392: J/K, which is used in the ideal gas law cyclical process process in which a system is brought back to its original state at the end of every cycle entropy measurement of a system's disorder and how much energy is not available to do work in a system first law of thermodynamics states that the change in internal energy of a system equals the net energy transfer by heat into the system minus the net work done by the system heat engine machine that uses energy transfer by heat to do work heat pump machine that generates the heat transfer of energy from cold to hot ideal gas law physical law that relates the pressure and volume of a gas to the number of gas molecules or atoms, or number of moles of gas, and the absolute temperature

  10. Heat pumps, air conditioners, and refrigerators transfer energy by heat in which direction?

    • In no particular direction
    • From low to high temperatures
    • Only within one reservoir
    • From hot to cold
    Reveal answer

    Answer: From low to high temperatures

    Source evidence

    PDF page 388: As noted, a cyclical process brings the system back to its original condition at the end of every cycle. Such a system’s internal energy, U, is the same at the beginning and end of every cycle—that is, . The first law of thermodynamics states that where Q is the net heat transfer during the cycle, and W is the net work done by the system. The net heat transfer is the energy transferred in by heat from the hot reservoir minus the amount that is transferred out to the cold reservoir ). Because there is no change in internal energy for a complete cycle ( ), we have ( 12.19 so that 12.20 Therefore, the net work done by the system equals the net heat into the system, or 12.21 for a cyclical process. Because the hot reservoir is heated externally, which is an energy-intensive process, it is important that the work be done as efficiently as possible. In fact, we want W to equal , and for there to be no heat to the environment (that is, ). Unfortunately, this is impossible. According to the second law of thermodynamics, heat engines cannot have perfect conversion of heat into work. Recall that entropy is a measure of the disorder of a system, which is also how much energy is unavailable to do work. The second law of thermodynamics requires that the total entropy of a system either increases or remains constant in any process. Therefore, there is a minimum amount of that cannot be used for work. The amount of heat rejected to the cold reservoir, depends upon the efficiency of the heat engine. The smaller the increase in entropy, , the smaller the value of , and the more heat energy is available to do work. Heat pumps, air conditioners, and refrigerators utilize heat transfer of energy from low to high temperatures, which is the

    PDF page 388: opposite of what heat engines do. Heat transfers energy from a cold reservoir and delivers energy into a hot one. This

  11. Transferring heat energy from a cold reservoir to a hot one requires what?

    • Work input
    • Only entropy
    • No energy at all
    • Light input
    Reveal answer

    Answer: Work input

    Source evidence

    PDF page 388: opposite of what heat engines do. Heat transfers energy from a cold reservoir and delivers energy into a hot one. This

    PDF page 388: requires work input, W, which produces a transfer of energy by heat. Therefore, the total heat transfer to the hot reservoir is 12.22 The purpose of a heat pump is to transfer energy by heat to a warm environment, such as a home in the winter. The great advantage of using a heat pump to keep your home warm rather than just burning fuel in a fireplace or furnace is that a heat pump supplies . Heat comes from the outside air, even at a temperature below freezing, to the indoor space. You only pay for W, and you get an additional heat transfer of from the outside at no cost. In many cases, at least twice as much energy is transferred to the heated space as is used to run the heat pump. When you burn fuel to keep warm, you pay for all of it. The disadvantage to a heat pump is that the work input (required by the second law of thermodynamics) is sometimes

  12. In a heat pump's outdoor coils (evaporator), heat entering the working fluid turns it into a:

    • Gas
    • Liquid
    • Solid
    • Plasma
    Reveal answer

    Answer: Gas

    Source evidence

    PDF page 389: more expensive than simply burning fuel, especially if the work is provided by electrical energy. The basic components of a heat pump are shown in Figure 12.15. A working fluid, such as a refrigerant, is used. In the outdoor coils (the evaporator), heat enters the working fluid from the cold outdoor air, turning it into a gas.

    PDF page 389: valve. In the heating mode, heat transfers to the working fluid in the evaporator (1) from the colder, outdoor air, turning it into a gas. The electrically driven compressor (2) increases the temperature and pressure of the gas and forces it into the condenser coils (3) inside the heated space. Because the temperature of the gas is higher than the temperature in the room, heat transfers energy from the gas to the room as the gas condenses into a liquid. The working fluid is then cooled as it flows back through an expansion valve (4) to the outdoor evaporator coils. The electrically driven compressor (work input W) raises the temperature and pressure of the gas and forces it into the condenser coils that are inside the heated space. Because the temperature of the gas is higher than the temperature inside the room, heat transfers energy to the room, and the gas condenses into a liquid. The liquid then flows back through an expansion (pressure-reducing) valve. The liquid, having been cooled through expansion, returns to the outdoor evaporator coils to resume the cycle. The quality of a heat pump is judged by how much energy is transferred by heat into the warm space ( ) compared with how much input work (W) is required.

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