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Centripetal Acceleration Quiz

12 questions physics Grades 9-12

The question sheet

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  1. Centripetal acceleration always points in what direction?

    • Opposite to the radius outward
    • Toward the center of curvature
    • Away from the center
    • Along the velocity vector
    Reveal answer

    Answer: Toward the center of curvature

    Source evidence

    PDF page 263: shown at two points along the path. Acceleration is in the direction of the change in velocity, which points directly toward the center of rotation (the center of the circular path). This pointing is shown with the vector diagram in the figure. We call the acceleration of an object moving in uniform circular motion (resulting from a net external force) the centripetal acceleration( ); centripetal means “toward the center” or “center seeking.”

    PDF page 264: The direction of centripetal acceleration is toward the center of curvature, but what is its magnitude? Note that the triangle formed by the velocity vectors and the one formed by the radii and are similar. Both the triangles ABC and PQR are isosceles triangles (two equal sides). The two equal sides of the velocity vector triangle are the speeds . Using the properties of two similar triangles, we obtain

  2. In uniform circular motion, what changes to produce an acceleration even at constant speed?

    • The radius of the path
    • The mass of the object
    • The direction of the velocity
    • The angular velocity
    Reveal answer

    Answer: The direction of the velocity

    Source evidence

    PDF page 263: We know from kinematics that acceleration is a change in velocity, either in its magnitude or in its direction, or both. In uniform circular motion, the direction of the velocity changes constantly, so there is always an associated acceleration, even though the magnitude of the velocity might be constant. You experience this acceleration yourself when you turn a corner in your car. (If you hold the wheel steady during a turn and move at constant speed, you are in uniform circular motion.) What you notice is a sideways acceleration because you and the car are changing direction. The sharper the curve and the greater your speed, the more noticeable this acceleration will become. In this section we examine the direction and magnitude of that acceleration.

  3. According to the source, acceleration is a change in velocity in which respect?

    • Neither magnitude nor direction
    • Only in magnitude
    • In magnitude, direction, or both
    • Only in direction
    Reveal answer

    Answer: In magnitude, direction, or both

    Source evidence

    PDF page 263: We know from kinematics that acceleration is a change in velocity, either in its magnitude or in its direction, or both. In uniform circular motion, the direction of the velocity changes constantly, so there is always an associated acceleration, even though the magnitude of the velocity might be constant. You experience this acceleration yourself when you turn a corner in your car. (If you hold the wheel steady during a turn and move at constant speed, you are in uniform circular motion.) What you notice is a sideways acceleration because you and the car are changing direction. The sharper the curve and the greater your speed, the more noticeable this acceleration will become. In this section we examine the direction and magnitude of that acceleration.

  4. The word 'centripetal' means what?

    • Along the tangent
    • Away from the center
    • Perpendicular to gravity
    • Toward the center, center seeking
    Reveal answer

    Answer: Toward the center, center seeking

    Source evidence

    PDF page 263: shown at two points along the path. Acceleration is in the direction of the change in velocity, which points directly toward the center of rotation (the center of the circular path). This pointing is shown with the vector diagram in the figure. We call the acceleration of an object moving in uniform circular motion (resulting from a net external force) the centripetal acceleration( ); centripetal means “toward the center” or “center seeking.”

  5. Centripetal acceleration is proportional to what power of the speed?

    • Inverse of speed
    • Speed directly
    • Square root of speed
    • Speed squared
    Reveal answer

    Answer: Speed squared

    Source evidence

    PDF page 264: which is the acceleration of an object in a circle of radius at a speed . So, centripetal acceleration is greater at high speeds and in sharp curves (smaller radius), as you have noticed when driving a car. But it is a bit surprising that is proportional to speed squared, implying, for example, that it is four times as hard to take a curve at 100 km/h than at 50 km/h. A sharp corner has a small radius, so that is greater for tighter turns, as you have probably noticed. It is also useful to express in terms of angular velocity. Substituting into the above expression, we find . We can express the magnitude of centripetal acceleration using either of two equations:

  6. How does centripetal acceleration change for a sharper curve?

    • It stays the same
    • It decreases
    • It becomes greater
    • It becomes zero
    Reveal answer

    Answer: It becomes greater

    Source evidence

    PDF page 264: which is the acceleration of an object in a circle of radius at a speed . So, centripetal acceleration is greater at high speeds and in sharp curves (smaller radius), as you have noticed when driving a car. But it is a bit surprising that is proportional to speed squared, implying, for example, that it is four times as hard to take a curve at 100 km/h than at 50 km/h. A sharp corner has a small radius, so that is greater for tighter turns, as you have probably noticed. It is also useful to express in terms of angular velocity. Substituting into the above expression, we find . We can express the magnitude of centripetal acceleration using either of two equations:

  7. The source says taking a curve at 100 km/h is how much harder than at 50 km/h?

    • Twice as hard
    • Eight times as hard
    • Four times as hard
    • Half as hard
    Reveal answer

    Answer: Four times as hard

    Source evidence

    PDF page 264: which is the acceleration of an object in a circle of radius at a speed . So, centripetal acceleration is greater at high speeds and in sharp curves (smaller radius), as you have noticed when driving a car. But it is a bit surprising that is proportional to speed squared, implying, for example, that it is four times as hard to take a curve at 100 km/h than at 50 km/h. A sharp corner has a small radius, so that is greater for tighter turns, as you have probably noticed. It is also useful to express in terms of angular velocity. Substituting into the above expression, we find . We can express the magnitude of centripetal acceleration using either of two equations:

  8. A tighter turn has a smaller radius, which makes centripetal acceleration do what?

    • Increase
    • Decrease
    • Vanish
    • Reverse direction
    Reveal answer

    Answer: Increase

    Source evidence

    PDF page 264: which is the acceleration of an object in a circle of radius at a speed . So, centripetal acceleration is greater at high speeds and in sharp curves (smaller radius), as you have noticed when driving a car. But it is a bit surprising that is proportional to speed squared, implying, for example, that it is four times as hard to take a curve at 100 km/h than at 50 km/h. A sharp corner has a small radius, so that is greater for tighter turns, as you have probably noticed. It is also useful to express in terms of angular velocity. Substituting into the above expression, we find . We can express the magnitude of centripetal acceleration using either of two equations:

  9. High centripetal acceleration in a centrifuge affects separation time how?

    • It doubles it
    • It has no effect
    • It significantly decreases it
    • It slightly increases it
    Reveal answer

    Answer: It significantly decreases it

    Source evidence

    PDF page 264: Recall that the direction of is toward the center. You may use whichever expression is more convenient, as illustrated in examples below. A centrifuge (see Figure 6.8b) is a rotating device used to separate specimens of different densities. High centripetal acceleration significantly decreases the time it takes for separation to occur, and makes separation possible with small samples. Centrifuges are used in a variety of applications in science and medicine, including the

  10. To express centripetal acceleration using angular velocity, what is substituted into the expression?

    • F = ma
    • v = r/ω
    • v = rω
    • a = v/r
    Reveal answer

    Answer: v = rω

    Source evidence

    PDF page 264: which is the acceleration of an object in a circle of radius at a speed . So, centripetal acceleration is greater at high speeds and in sharp curves (smaller radius), as you have noticed when driving a car. But it is a bit surprising that is proportional to speed squared, implying, for example, that it is four times as hard to take a curve at 100 km/h than at 50 km/h. A sharp corner has a small radius, so that is greater for tighter turns, as you have probably noticed. It is also useful to express in terms of angular velocity. Substituting into the above expression, we find . We can express the magnitude of centripetal acceleration using either of two equations:

  11. According to Newton's second law, what is needed to cause a centripetal acceleration?

    • A larger radius
    • A change in mass
    • A constant velocity
    • A net external force
    Reveal answer

    Answer: A net external force

    Source evidence

    PDF page 267: Of course, a net external force is needed to cause any acceleration, just as Newton proposed in his second law of motion. So a net external force is needed to cause a centripetal acceleration. In Centripetal Force, we will consider the forces involved in circular motion.

  12. In the ultracentrifuge example, angular velocity was converted from rev/min to what units?

    • Degrees per minute
    • Cycles per hour
    • Radians per second
    • Meters per second
    Reveal answer

    Answer: Radians per second

    Source evidence

    PDF page 266: Calculate the centripetal acceleration of a point 7.50 cm from the axis of an ultracentrifuge spinning at Determine the ratio of this acceleration to that due to gravity. See Figure 6.8(b). Strategy The term rev/min stands for revolutions per minute. By converting this to radians per second, we obtain the angular velocity . Because is given, we can use the second expression in the equation to calculate the centripetal acceleration. Solution

    PDF page 266: To convert to radians per second, we use the facts that one revolution is and one minute is 60.0 s. Thus,

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