Centripetal Force Quiz

PDF page 267: Any force or combination of forces can cause a centripetal or radial acceleration. Just a few examples are the tension in the rope on a tether ball, the force of Earth’s gravity on the Moon, friction between roller skates and a rink floor, a banked roadway’s force on a car, and forces on the tube of a spinning centrifuge. Any net force causing uniform circular motion is called a centripetal force. The direction of a centripetal force is toward the center of curvature, the same as the direction of centripetal acceleration. According to Newton’s second law of motion, net force is mass times acceleration: net . For uniform circular motion, the acceleration is the centripetal acceleration— . Thus, the magnitude of centripetal force is 6.23

PDF page 267: Any force or combination of forces can cause a centripetal or radial acceleration. Just a few examples are the tension in the rope on a tether ball, the force of Earth’s gravity on the Moon, friction between roller skates and a rink floor, a banked roadway’s force on a car, and forces on the tube of a spinning centrifuge. Any net force causing uniform circular motion is called a centripetal force. The direction of a centripetal force is toward the center of curvature, the same as the direction of centripetal acceleration. According to Newton’s second law of motion, net force is mass times acceleration: net . For uniform circular motion, the acceleration is the centripetal acceleration— . Thus, the magnitude of centripetal force is 6.23

PDF page 267: Any force or combination of forces can cause a centripetal or radial acceleration. Just a few examples are the tension in the rope on a tether ball, the force of Earth’s gravity on the Moon, friction between roller skates and a rink floor, a banked roadway’s force on a car, and forces on the tube of a spinning centrifuge. Any net force causing uniform circular motion is called a centripetal force. The direction of a centripetal force is toward the center of curvature, the same as the direction of centripetal acceleration. According to Newton’s second law of motion, net force is mass times acceleration: net . For uniform circular motion, the acceleration is the centripetal acceleration— . Thus, the magnitude of centripetal force is 6.23

PDF page 267: Any force or combination of forces can cause a centripetal or radial acceleration. Just a few examples are the tension in the rope on a tether ball, the force of Earth’s gravity on the Moon, friction between roller skates and a rink floor, a banked roadway’s force on a car, and forces on the tube of a spinning centrifuge. Any net force causing uniform circular motion is called a centripetal force. The direction of a centripetal force is toward the center of curvature, the same as the direction of centripetal acceleration. According to Newton’s second law of motion, net force is mass times acceleration: net . For uniform circular motion, the acceleration is the centripetal acceleration— . Thus, the magnitude of centripetal force is 6.23

PDF page 267: By using the expressions for centripetal acceleration from , we get two expressions for the centripetal force in terms of mass, velocity, angular velocity, and radius of curvature:

PDF page 267: You may use whichever expression for centripetal force is more convenient. Centripetal force is always perpendicular to the path and pointing to the center of curvature, because is perpendicular to the velocity and

PDF page 268: pointing to the center of curvature. Note that if you solve the first expression for , you get

PDF page 268: This implies that for a given mass and velocity, a large centripetal force causes a small radius of curvature—that is, a tight curve.

PDF page 268: FIGURE 6.9 The frictional force supplies the centripetal force and is numerically equal to it. Centripetal force is perpendicular to velocity

PDF page 268: and causes uniform circular motion. The larger the , the smaller the radius of curvature and the sharper the curve. The second curve has the same , but a larger produces a smaller .

PDF page 268: This implies that for a given mass and velocity, a large centripetal force causes a small radius of curvature—that is, a tight curve.

PDF page 268: (a) Calculate the centripetal force exerted on a 900 kg car that negotiates a 500 m radius curve at 25.0 m/s.

PDF page 268: Figure 6.10 shows the forces acting on the car on an unbanked (level ground) curve. Friction is to the left, keeping

PDF page 268: the car from slipping, and because it is the only horizontal force acting on the car, the friction is the centripetal force in this case. We know that the maximum static friction (at which the tires roll but do not slip) is , where is the static coefficient of friction and N is the normal force. The normal force equals the car’s weight on level ground, so that . Thus the centripetal force in this situation is

PDF page 268: the car from slipping, and because it is the only horizontal force acting on the car, the friction is the centripetal force in this case. We know that the maximum static friction (at which the tires roll but do not slip) is , where is the static coefficient of friction and N is the normal force. The normal force equals the car’s weight on level ground, so that . Thus the centripetal force in this situation is