The Second Condition for Equilibrium Quiz
The question sheet
Reveal any answer as you study-
What does the second condition necessary for equilibrium require?
- All forces act at the pivot
- Net external torque must be zero
- Angular velocity must be zero
- Net force must be positive
Reveal answer
Answer: Net external torque must be zero
Source evidence
PDF page 403: shown as a dashed line in Figure 9.6 and Figure 9.7. Note that the line segment that defines the distance is perpendicular to , as its name implies. It is sometimes easier to find or visualize than to find both and . In such cases, it may be more convenient to use rather than for torque, but both are equally valid. The SI unit of torque is newtons times meters, usually written as . For example, if you push perpendicular to the door with a force of 40 N at a distance of 0.800 m from the hinges, you exert a torque of 32 N·m(0.800 m × 40 N × sin 90o) relative to the hinges. If you reduce the force to 20 N, the torque is reduced to , and so on. The torque is always calculated with reference to some chosen pivot point. For the same applied force, a different choice for the location of the pivot will give you a different value for the torque, since both and depend on the location of the pivot. Any point in any object can be chosen to calculate the torque about that point. The object may not actually pivot about the chosen “pivot point.” Note that for rotation in a plane, torque has two possible directions. Torque is either clockwise or counterclockwise relative to the chosen pivot point, as illustrated for points B and A, respectively, in Figure 9.7. If the object can rotate about point A, it will rotate counterclockwise, which means that the torque for the force is shown as counterclockwise relative to A. But if the object can rotate about point B, it will rotate clockwise, which means the torque for the force shown is clockwise relative to B. Also, the magnitude of the torque is greater when the lever arm is longer. Now, the second condition necessary to achieve equilibrium is that the net external torque on a system must be zero. An external torque is one that is created by an external force. You can choose the point around which the torque is calculated. The point can be the physical pivot point of a system or any other point in space—but it must be the same point for all torques. If the second condition (net external torque on a system is zero) is satisfied for one
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According to the source, a rotating body can be in equilibrium if its rate of rotation is what?
- Always counterclockwise
- Increasing steadily
- Zero at all times
- Constant and unchanged by forces
Reveal answer
Answer: Constant and unchanged by forces
Source evidence
PDF page 402: The second condition necessary to achieve equilibrium involves avoiding accelerated rotation (maintaining a constant angular velocity). A rotating body or system can be in equilibrium if its rate of rotation is constant and remains unchanged by the forces acting on it. To understand what factors affect rotation, let us think about what happens when you open an ordinary door by rotating it on its hinges.
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What is torque described as in the source?
- The mass of an object
- A type of linear velocity
- The turning effectiveness of a force
- A form of static friction
Reveal answer
Answer: The turning effectiveness of a force
Source evidence
PDF page 402: FIGURE 9.6 Torque is the turning or twisting effectiveness of a force, illustrated here for door rotation on its hinges (as viewed from
PDF page 402: overhead). Torque has both magnitude and direction. (a) Counterclockwise torque is produced by this force, which means that the door will rotate in a counterclockwise due to . Note that is the perpendicular distance of the pivot from the line of action of the force. (b) A smaller counterclockwise torque is produced by a smaller force acting at the same distance from the hinges (the pivot point). (c) The same force as in (a) produces a smaller counterclockwise torque when applied at a smaller distance from the hinges. (d) The same force as in (a), but acting in the opposite direction, produces a clockwise torque. (e) A smaller counterclockwise torque is produced by the same magnitude force acting at the same point but in a different direction. Here, is less than . (f) Torque is zero here since the force just pulls on the hinges, producing no rotation. In this case, . The magnitude, direction, and point of application of the force are incorporated into the definition of the physical quantity called torque. Torque is the rotational equivalent of a force. It is a measure of the effectiveness of a force in changing or accelerating a rotation (changing the angular velocity over a period of time). In equation form, the
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Torque is the rotational equivalent of what?
- A force
- A displacement
- A mass
- An acceleration
Reveal answer
Answer: A force
Source evidence
PDF page 402: overhead). Torque has both magnitude and direction. (a) Counterclockwise torque is produced by this force, which means that the door will rotate in a counterclockwise due to . Note that is the perpendicular distance of the pivot from the line of action of the force. (b) A smaller counterclockwise torque is produced by a smaller force acting at the same distance from the hinges (the pivot point). (c) The same force as in (a) produces a smaller counterclockwise torque when applied at a smaller distance from the hinges. (d) The same force as in (a), but acting in the opposite direction, produces a clockwise torque. (e) A smaller counterclockwise torque is produced by the same magnitude force acting at the same point but in a different direction. Here, is less than . (f) Torque is zero here since the force just pulls on the hinges, producing no rotation. In this case, . The magnitude, direction, and point of application of the force are incorporated into the definition of the physical quantity called torque. Torque is the rotational equivalent of a force. It is a measure of the effectiveness of a force in changing or accelerating a rotation (changing the angular velocity over a period of time). In equation form, the
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Which factor is NOT listed as affecting how effectively you open a door?
- The direction you push
- The color of the door
- The size of the force
- The point where you push
Reveal answer
Answer: The color of the door
Source evidence
PDF page 402: Several familiar factors determine how effective you are in opening the door. See Figure 9.6. First of all, the larger the force, the more effective it is in opening the door—obviously, the harder you push, the more rapidly the door opens. Also, the point at which you push is crucial. If you apply your force too close to the hinges, the door will open slowly, if at all. Most people have been embarrassed by making this mistake and bumping up against a door when it did not open as quickly as expected. Finally, the direction in which you push is also important. The most effective direction is perpendicular to the door—we push in this direction almost instinctively.
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The most effective direction to push a door is what relative to the door?
- Perpendicular
- Parallel
- At 45 degrees
- Toward the hinges
Reveal answer
Answer: Perpendicular
Source evidence
PDF page 402: Several familiar factors determine how effective you are in opening the door. See Figure 9.6. First of all, the larger the force, the more effective it is in opening the door—obviously, the harder you push, the more rapidly the door opens. Also, the point at which you push is crucial. If you apply your force too close to the hinges, the door will open slowly, if at all. Most people have been embarrassed by making this mistake and bumping up against a door when it did not open as quickly as expected. Finally, the direction in which you push is also important. The most effective direction is perpendicular to the door—we push in this direction almost instinctively.
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What happens if you apply your force too close to the hinges?
- The door opens faster
- The door opens slowly, if at all
- The torque is maximized
- The door rotates backward
Reveal answer
Answer: The door opens slowly, if at all
Source evidence
PDF page 402: Several familiar factors determine how effective you are in opening the door. See Figure 9.6. First of all, the larger the force, the more effective it is in opening the door—obviously, the harder you push, the more rapidly the door opens. Also, the point at which you push is crucial. If you apply your force too close to the hinges, the door will open slowly, if at all. Most people have been embarrassed by making this mistake and bumping up against a door when it did not open as quickly as expected. Finally, the direction in which you push is also important. The most effective direction is perpendicular to the door—we push in this direction almost instinctively.
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What is the SI unit of torque?
- Kilograms
- Newton times meters
- Joules
- Newtons per meter
Reveal answer
Answer: Newton times meters
Source evidence
PDF page 403: shown as a dashed line in Figure 9.6 and Figure 9.7. Note that the line segment that defines the distance is perpendicular to , as its name implies. It is sometimes easier to find or visualize than to find both and . In such cases, it may be more convenient to use rather than for torque, but both are equally valid. The SI unit of torque is newtons times meters, usually written as . For example, if you push perpendicular to the door with a force of 40 N at a distance of 0.800 m from the hinges, you exert a torque of 32 N·m(0.800 m × 40 N × sin 90o) relative to the hinges. If you reduce the force to 20 N, the torque is reduced to , and so on. The torque is always calculated with reference to some chosen pivot point. For the same applied force, a different choice for the location of the pivot will give you a different value for the torque, since both and depend on the location of the pivot. Any point in any object can be chosen to calculate the torque about that point. The object may not actually pivot about the chosen “pivot point.” Note that for rotation in a plane, torque has two possible directions. Torque is either clockwise or counterclockwise relative to the chosen pivot point, as illustrated for points B and A, respectively, in Figure 9.7. If the object can rotate about point A, it will rotate counterclockwise, which means that the torque for the force is shown as counterclockwise relative to A. But if the object can rotate about point B, it will rotate clockwise, which means the torque for the force shown is clockwise relative to B. Also, the magnitude of the torque is greater when the lever arm is longer. Now, the second condition necessary to achieve equilibrium is that the net external torque on a system must be zero. An external torque is one that is created by an external force. You can choose the point around which the torque is calculated. The point can be the physical pivot point of a system or any other point in space—but it must be the same point for all torques. If the second condition (net external torque on a system is zero) is satisfied for one
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The perpendicular lever arm is the shortest distance from the pivot to what?
- The hinges
- The applied force's endpoint
- The center of gravity
- The line along which the force acts
Reveal answer
Answer: The line along which the force acts
Source evidence
PDF page 403: The perpendicular lever arm is the shortest distance from the pivot point to the line along which acts; it is
PDF page 403: shown as a dashed line in Figure 9.6 and Figure 9.7. Note that the line segment that defines the distance is perpendicular to , as its name implies. It is sometimes easier to find or visualize than to find both and . In such cases, it may be more convenient to use rather than for torque, but both are equally valid. The SI unit of torque is newtons times meters, usually written as . For example, if you push perpendicular to the door with a force of 40 N at a distance of 0.800 m from the hinges, you exert a torque of 32 N·m(0.800 m × 40 N × sin 90o) relative to the hinges. If you reduce the force to 20 N, the torque is reduced to , and so on. The torque is always calculated with reference to some chosen pivot point. For the same applied force, a different choice for the location of the pivot will give you a different value for the torque, since both and depend on the location of the pivot. Any point in any object can be chosen to calculate the torque about that point. The object may not actually pivot about the chosen “pivot point.” Note that for rotation in a plane, torque has two possible directions. Torque is either clockwise or counterclockwise relative to the chosen pivot point, as illustrated for points B and A, respectively, in Figure 9.7. If the object can rotate about point A, it will rotate counterclockwise, which means that the torque for the force is shown as counterclockwise relative to A. But if the object can rotate about point B, it will rotate clockwise, which means the torque for the force shown is clockwise relative to B. Also, the magnitude of the torque is greater when the lever arm is longer. Now, the second condition necessary to achieve equilibrium is that the net external torque on a system must be zero. An external torque is one that is created by an external force. You can choose the point around which the torque is calculated. The point can be the physical pivot point of a system or any other point in space—but it must be the same point for all torques. If the second condition (net external torque on a system is zero) is satisfied for one
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By common convention, counterclockwise torques are assigned what sign?
- Positive
- Negative
- Variable
- Zero
Reveal answer
Answer: Positive
Source evidence
PDF page 404: choice of pivot point, it will also hold true for any other choice of pivot point in or out of the system of interest. (This is true only in an inertial frame of reference.) The second condition necessary to achieve equilibrium is stated in equation form as 9.6 where net means total. Torques, which are in opposite directions are assigned opposite signs. A common convention is to call counterclockwise (ccw) torques positive and clockwise (cw) torques negative. When two children balance a seesaw as shown in Figure 9.8, they satisfy the two conditions for equilibrium. Most people have perfect intuition about seesaws, knowing that the lighter child must sit farther from the pivot and that a heavier child can keep a lighter one off the ground indefinitely.
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The magnitude of torque is greater when the lever arm is what?
- Longer
- Negative
- Shorter
- Zero
Reveal answer
Answer: Longer
Source evidence
PDF page 403: shown as a dashed line in Figure 9.6 and Figure 9.7. Note that the line segment that defines the distance is perpendicular to , as its name implies. It is sometimes easier to find or visualize than to find both and . In such cases, it may be more convenient to use rather than for torque, but both are equally valid. The SI unit of torque is newtons times meters, usually written as . For example, if you push perpendicular to the door with a force of 40 N at a distance of 0.800 m from the hinges, you exert a torque of 32 N·m(0.800 m × 40 N × sin 90o) relative to the hinges. If you reduce the force to 20 N, the torque is reduced to , and so on. The torque is always calculated with reference to some chosen pivot point. For the same applied force, a different choice for the location of the pivot will give you a different value for the torque, since both and depend on the location of the pivot. Any point in any object can be chosen to calculate the torque about that point. The object may not actually pivot about the chosen “pivot point.” Note that for rotation in a plane, torque has two possible directions. Torque is either clockwise or counterclockwise relative to the chosen pivot point, as illustrated for points B and A, respectively, in Figure 9.7. If the object can rotate about point A, it will rotate counterclockwise, which means that the torque for the force is shown as counterclockwise relative to A. But if the object can rotate about point B, it will rotate clockwise, which means the torque for the force shown is clockwise relative to B. Also, the magnitude of the torque is greater when the lever arm is longer. Now, the second condition necessary to achieve equilibrium is that the net external torque on a system must be zero. An external torque is one that is created by an external force. You can choose the point around which the torque is calculated. The point can be the physical pivot point of a system or any other point in space—but it must be the same point for all torques. If the second condition (net external torque on a system is zero) is satisfied for one
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Pushing a force of 40 N perpendicular at 0.800 m from the hinges gives what torque?
- 20 N·m
- 32 N·m
- 0.8 N·m
- 40 N·m
Reveal answer
Answer: 32 N·m
Source evidence
PDF page 403: shown as a dashed line in Figure 9.6 and Figure 9.7. Note that the line segment that defines the distance is perpendicular to , as its name implies. It is sometimes easier to find or visualize than to find both and . In such cases, it may be more convenient to use rather than for torque, but both are equally valid. The SI unit of torque is newtons times meters, usually written as . For example, if you push perpendicular to the door with a force of 40 N at a distance of 0.800 m from the hinges, you exert a torque of 32 N·m(0.800 m × 40 N × sin 90o) relative to the hinges. If you reduce the force to 20 N, the torque is reduced to , and so on. The torque is always calculated with reference to some chosen pivot point. For the same applied force, a different choice for the location of the pivot will give you a different value for the torque, since both and depend on the location of the pivot. Any point in any object can be chosen to calculate the torque about that point. The object may not actually pivot about the chosen “pivot point.” Note that for rotation in a plane, torque has two possible directions. Torque is either clockwise or counterclockwise relative to the chosen pivot point, as illustrated for points B and A, respectively, in Figure 9.7. If the object can rotate about point A, it will rotate counterclockwise, which means that the torque for the force is shown as counterclockwise relative to A. But if the object can rotate about point B, it will rotate clockwise, which means the torque for the force shown is clockwise relative to B. Also, the magnitude of the torque is greater when the lever arm is longer. Now, the second condition necessary to achieve equilibrium is that the net external torque on a system must be zero. An external torque is one that is created by an external force. You can choose the point around which the torque is calculated. The point can be the physical pivot point of a system or any other point in space—but it must be the same point for all torques. If the second condition (net external torque on a system is zero) is satisfied for one
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