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Uniform Circular Motion and Simple Harmonic Motion Quiz

12 questions physics Grades 9-12

The question sheet

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  1. What can be used to easily produce simple harmonic motion?

    • Free fall
    • Random vibration
    • Uniform circular motion
    • Constant velocity in a line
    Reveal answer

    Answer: Uniform circular motion

    Source evidence

    PDF page 757: There is an easy way to produce simple harmonic motion by using uniform circular motion. Figure 16.16 shows one way of using this method. A ball is attached to a uniformly rotating vertical turntable, and its shadow is projected on the floor as shown. The shadow undergoes simple harmonic motion. Hooke’s law usually describes uniform circular motions ( constant) rather than systems that have large visible displacements. So observing the projection of uniform circular motion, as in Figure 16.16, is often easier than observing a precise large-scale simple harmonic oscillator. If studied in sufficient depth, simple harmonic motion produced in this manner can give considerable insight into many aspects of oscillations and waves and is very useful mathematically. In our brief treatment, we shall indicate some of the major features of this relationship and how they might be useful.

  2. In the turntable example, what undergoes simple harmonic motion?

    • The turntable
    • The shadow of the ball
    • The ball itself
    • The vertical axis
    Reveal answer

    Answer: The shadow of the ball

    Source evidence

    PDF page 757: There is an easy way to produce simple harmonic motion by using uniform circular motion. Figure 16.16 shows one way of using this method. A ball is attached to a uniformly rotating vertical turntable, and its shadow is projected on the floor as shown. The shadow undergoes simple harmonic motion. Hooke’s law usually describes uniform circular motions ( constant) rather than systems that have large visible displacements. So observing the projection of uniform circular motion, as in Figure 16.16, is often easier than observing a precise large-scale simple harmonic oscillator. If studied in sufficient depth, simple harmonic motion produced in this manner can give considerable insight into many aspects of oscillations and waves and is very useful mathematically. In our brief treatment, we shall indicate some of the major features of this relationship and how they might be useful.

  3. The point P travels around the circle at what kind of angular velocity?

    • Constant
    • Decreasing
    • Zero
    • Increasing
    Reveal answer

    Answer: Constant

    Source evidence

    PDF page 757: P travels around the circle at constant angular velocity . The point P is analogous to an object on the merry-goround. The projection of the position of P onto a fixed axis undergoes simple harmonic motion and is analogous to the shadow of the object. At the time shown in the figure, the projection has position and moves to the left with velocity . The velocity of the point P around the circle equals .The projection of on the -axis is the velocity of the simple harmonic motion along the -axis.

  4. The projection of point P onto a fixed axis undergoes what?

    • Simple harmonic motion
    • Free fall
    • Random motion
    • Uniform circular motion
    Reveal answer

    Answer: Simple harmonic motion

    Source evidence

    PDF page 757: P travels around the circle at constant angular velocity . The point P is analogous to an object on the merry-goround. The projection of the position of P onto a fixed axis undergoes simple harmonic motion and is analogous to the shadow of the object. At the time shown in the figure, the projection has position and moves to the left with velocity . The velocity of the point P around the circle equals .The projection of on the -axis is the velocity of the simple harmonic motion along the -axis.

  5. The shadow of the object is analogous to what?

    • The angular velocity
    • The circle's radius
    • The turntable
    • The projection of P's position
    Reveal answer

    Answer: The projection of P's position

    Source evidence

    PDF page 757: P travels around the circle at constant angular velocity . The point P is analogous to an object on the merry-goround. The projection of the position of P onto a fixed axis undergoes simple harmonic motion and is analogous to the shadow of the object. At the time shown in the figure, the projection has position and moves to the left with velocity . The velocity of the point P around the circle equals .The projection of on the -axis is the velocity of the simple harmonic motion along the -axis.

  6. The triangle formed by velocities and the triangle formed by displacements are what?

    • Obtuse triangles
    • Similar right triangles
    • Congruent equilateral
    • Unrelated
    Reveal answer

    Answer: Similar right triangles

    Source evidence

    PDF page 758: on the x-axis undergoes simple harmonic motion. Also shown is the velocity of this point around the circle, , and its projection, which is . Note that these velocities form a similar triangle to the displacement triangle. To see that the projection undergoes simple harmonic motion, note that its position is given by 16.48 where

    PDF page 758: versus indicates. Now let us use Figure 16.17 to do some further analysis of uniform circular motion as it relates to simple harmonic motion. The triangle formed by the velocities in the figure and the triangle formed by the displacements ( and ) are similar right triangles. Taking ratios of similar sides, we see that

  7. Angular velocity is measured in what units?

    • Degrees per revolution
    • Meters per second
    • Radians per unit time
    • Newtons
    Reveal answer

    Answer: Radians per unit time

    Source evidence

    PDF page 758: The angular velocity is in radians per unit time; in this case radians is the time for one revolution . That is,

  8. The expression for the projection's position matches which motion?

    • Damped free fall
    • Projectile motion
    • Uniform circular motion
    • A simple harmonic oscillator
    Reveal answer

    Answer: A simple harmonic oscillator

    Source evidence

    PDF page 758: This expression is the same one we had for the position of a simple harmonic oscillator in Simple Harmonic Motion: A Special Periodic Motion. If we make a graph of position versus time as in Figure 16.18, we see again the wavelike character (typical of simple harmonic motion) of the projection of uniform circular motion onto the -axis.

  9. The graph of position versus time of the projection shows what character?

    • Random spikes
    • Straight-line
    • Exponential decay
    • Wavelike
    Reveal answer

    Answer: Wavelike

    Source evidence

    PDF page 758: This expression is the same one we had for the position of a simple harmonic oscillator in Simple Harmonic Motion: A Special Periodic Motion. If we make a graph of position versus time as in Figure 16.18, we see again the wavelike character (typical of simple harmonic motion) of the projection of uniform circular motion onto the -axis.

    PDF page 758: FIGURE 16.18 The position of the projection of uniform circular motion performs simple harmonic motion, as this wavelike graph of

  10. The speed expression for the simple harmonic oscillator matches which method?

    • Conservation of energy
    • Hooke's law directly
    • Kinetic theory
    • Newton's second law
    Reveal answer

    Answer: Conservation of energy

    Source evidence

    PDF page 759: This expression for the speed of a simple harmonic oscillator is exactly the same as the equation obtained from conservation of energy considerations in Energy and the Simple Harmonic Oscillator.You can begin to see that it is possible to get all of the characteristics of simple harmonic motion from an analysis of the projection of uniform circular motion. Finally, let us consider the period of the motion of the projection. This period is the time it takes the point P to complete one revolution. That time is the circumference of the circle divided by the velocity around the circle, . Thus, the period is

  11. The period of the projection's motion is the time for point P to do what?

    • Stop moving
    • Reverse direction
    • Reach maximum speed
    • Complete one revolution
    Reveal answer

    Answer: Complete one revolution

    Source evidence

    PDF page 759: This expression for the speed of a simple harmonic oscillator is exactly the same as the equation obtained from conservation of energy considerations in Energy and the Simple Harmonic Oscillator.You can begin to see that it is possible to get all of the characteristics of simple harmonic motion from an analysis of the projection of uniform circular motion. Finally, let us consider the period of the motion of the projection. This period is the time it takes the point P to complete one revolution. That time is the circumference of the circle divided by the velocity around the circle, . Thus, the period is

  12. The period found for the projection compares to a simple harmonic oscillator how?

    • It is larger
    • It is zero
    • It is smaller
    • It is the same
    Reveal answer

    Answer: It is the same

    Source evidence

    PDF page 759: Thus, the period of the motion is the same as for a simple harmonic oscillator. We have determined the period for any simple harmonic oscillator using the relationship between uniform circular motion and simple harmonic motion. Some modules occasionally refer to the connection between uniform circular motion and simple harmonic motion. Moreover, if you carry your study of physics and its applications to greater depths, you will find this relationship useful. It can, for example, help to analyze how waves add when they are superimposed.

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