HSA.CED.A.4 Math Practice Questions

Practice playeasy

The simple interest formula is $I = Prt$ , where $I$ is interest, $P$ is principal, $r$ is rate, and $t$ is time. Which equation expresses $r$ in terms of $I$ , $P$ , and $t$ ?

The factors $P$ , $r$ , and $t$ are multiplied, so $r$ is isolated by using the inverse operation (division) on both sides of the equation $\dfrac{I}{\textcolor{red}{Pt}} = \dfrac{Prt}{\textcolor{red}{Pt}}$ . Simplifying gives $r = \dfrac{I}{Pt}$ .

Practice playeasy

Given $a^{2} + b^{2} = c^{2}$ , for all positive values of $a$ , $b$ , and $c$ , which equation solves for $a$ ?

Subtract $b^{2}$ from both sides: $a^{2} = c^{2} - b^{2}$ . Take the positive square root: $a = \sqrt{c^{2} - b^{2}}$ .

Practice playmedium

The equation $y = mx + b$ is in slope-intercept form. Which equation expresses $x$ in terms of $y$ , $m$ , and $b$ ?

The term $b$ is added, so $mx$ is isolated by using the inverse operation (subtraction) on both sides, $y - \textcolor{red}{b} = mx$ . Then, $m$ and $x$ are multiplied, so $x$ is isolated by using the inverse operation (division) on both sides, $\dfrac{y - b}{\textcolor{red}{m}} = \dfrac{mx}{\textcolor{red}{m}}$ . Simplifying gives $x = \dfrac{y - b}{m}$ .

Practice playeasy

Given $a^{2} + b^{2} = c^{2}$ , for all positive values of $a$ , $b$ , and $c$ , which equation solves for $b$ ?

Subtract $a^{2}$ from both sides: $b^{2} = c^{2} - a^{2}$ . Take the positive square root: $b = \sqrt{c^{2} - a^{2}}$ .

Practice playmedium

The perimeter formula for a rectangle is $P = 2l + 2w$ . Which equation expresses $w$ in terms of $P$ and $l$ ?

The term $2l$ is added, so $2w$ is isolated by using the inverse operation (subtraction) on both sides, $P - \textcolor{red}{2l} = 2w$ . Then, $2$ and $w$ are multiplied, so $w$ is isolated by using the inverse operation (division) on both sides, $\dfrac{P - 2l}{\textcolor{red}{2}} = \dfrac{2w}{\textcolor{red}{2}}$ . Simplifying gives $w = \dfrac{P - 2l}{2}$ .

Practice playeasy

Given $I = mr^{2}$ , for all positive values of $I$ , $m$ , and $r$ , which equation solves for $r$ ?

Divide both sides by $m$ : $r^{2} = \dfrac{I}{m}$ . Take the positive square root: $r = \sqrt{\dfrac{I}{m}}$ .

Practice playmedium

The equation $ax + b = c$ relates values $a$ , $b$ , $c$ , and $x$ . Which equation expresses $x$ in terms of $a$ , $b$ , and $c$ ?

The term $b$ is added, so $ax$ is isolated by using the inverse operation (subtraction) on both sides, $c - \textcolor{red}{b} = ax$ . Then, $a$ and $x$ are multiplied, so $x$ is isolated by using the inverse operation (division) on both sides, $\dfrac{c - b}{\textcolor{red}{a}} = \dfrac{ax}{\textcolor{red}{a}}$ . Simplifying gives $x = \dfrac{c - b}{a}$ .

Practice playmedium

Given $E = \dfrac{1}{2}mv^{2} + E_{0}$ , for all positive values of $E$ , $m$ , $v$ , and $E_{0}$ , which equation solves for $v$ ?

Subtract $E_{0}$ from both sides: $E - E_{0} = \dfrac{1}{2}mv^{2}$ . Multiply both sides by $2$ : $2(E - E_{0}) = mv^{2}$ . Divide by $m$ : $v^{2} = \dfrac{2(E - E_{0})}{m}$ . Take the positive square root: $v = \sqrt{\dfrac{2(E - E_{0})}{m}}$ .

HSA.CED.A.4 math practice. Learn by doing.

Skills aligned to HSA.CED.A.4

Literal equations (SAT)

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