Literal quadratic equations (ACT). Game on.

Literal quadratic equations (ACT) is a grade 9 math skill aligned to Common Core standard HSA.CED.A.4: rearrange formulas to highlight a quantity of interest, using the same reasoning as in solving equations. Below are 8 practice questions with answers and step-by-step explanations, drawn from the 10 literal quadratic equations (act) problems our math games drill.

CCSS HSA.CED.A.410 questions in the bank
Kickoff

8 plays. No signup.

Warm-upeasy

Given a2+b2=c2a^{2} + b^{2} = c^{2}, for all positive values of aa, bb, and cc, which equation correctly solves for aa?

Subtract b2b^{2} from both sides: a2=c2b2a^{2} = c^{2} - b^{2}. Take the positive square root: a=c2b2a = \sqrt{c^{2} - b^{2}}.

Mid-gameeasy

Given a2+b2=c2a^{2} + b^{2} = c^{2}, for all positive values of aa, bb, and cc, which equation correctly solves for bb?

Subtract a2a^{2} from both sides: b2=c2a2b^{2} = c^{2} - a^{2}. Take the positive square root: b=c2a2b = \sqrt{c^{2} - a^{2}}.

Mid-gameeasy

Given I=mr2I = mr^{2}, for all positive values of II, mm, and rr, which equation correctly solves for rr?

Divide both sides by mm: r2=Imr^{2} = \dfrac{I}{m}. Take the positive square root: r=Imr = \sqrt{\dfrac{I}{m}}.

Mid-gamemedium

Given E=12mv2+E0E = \dfrac{1}{2}mv^{2} + E_{0}, for all positive values of EE, mm, vv, and E0E_{0}, which equation correctly solves for vv?

Subtract E0E_{0} from both sides: EE0=12mv2E - E_{0} = \dfrac{1}{2}mv^{2}. Multiply both sides by 22: 2(EE0)=mv22(E - E_{0}) = mv^{2}. Divide by mm: v2=2(EE0)mv^{2} = \dfrac{2(E - E_{0})}{m}. Take the positive square root: v=2(EE0)mv = \sqrt{\dfrac{2(E - E_{0})}{m}}.

Mid-gamemedium

Given V=πr2hV = \pi r^{2} h, for all positive values of VV, rr, and hh, which equation correctly solves for rr?

Divide both sides by πh\pi h: r2=Vπhr^{2} = \dfrac{V}{\pi h}. Take the positive square root: r=Vπhr = \sqrt{\dfrac{V}{\pi h}}.

Mid-gamemedium

Given A=4πr2A = 4\pi r^{2}, for all positive values of AA and rr, which equation correctly solves for rr?

Divide both sides by 4π4\pi: r2=A4πr^{2} = \dfrac{A}{4\pi}. Take the positive square root: r=A4πr = \sqrt{\dfrac{A}{4\pi}}.

Mid-gamemedium

Given d=12gt2d = \dfrac{1}{2}gt^{2}, for all positive values of dd, gg, and tt, which equation correctly solves for tt?

Multiply both sides by 22: 2d=gt22d = gt^{2}. Divide by gg: t2=2dgt^{2} = \dfrac{2d}{g}. Take the positive square root: t=2dgt = \sqrt{\dfrac{2d}{g}}.

Buzzer beatermedium

Given P=kr2P = \dfrac{k}{r^{2}}, for all positive values of kk, rr, and PP, which equation correctly solves for rr?

Multiply both sides by r2r^{2}: Pr2=kPr^{2} = k. Divide by PP: r2=kPr^{2} = \dfrac{k}{P}. Take the positive square root: r=kPr = \sqrt{\dfrac{k}{P}}.

Drill it inside a game.

The free placement test finds your level, then every match serves literal quadratic equations (act) questions at exactly the right difficulty.