TCAP Grade 7 Geometry. Practice it free.

Draw, construct, and describe geometrical figures and solve problems involving angle measure, area, surface area, and volume. This Grade 7 reporting domain maps to 9 practice skills and 8 representative questions from the playable bank.

Grade 79 mapped skills
What the test measures

Geometry skills

  1. 7.G.A.1 Solve problems involving scale drawings

  2. 7.G.A.2 Draw geometric shapes with given conditions

  3. 7.G.A.3 Describe the two-dimensional figures that result from slices of three-dimensional figures

  4. 7.G.B.4 Know the formulas for the area and circumference of a circle

  5. 7.G.B.5 Use facts about supplementary, complementary, vertical, and adjacent angles

  6. 7.G.B.6 Solve real-world and mathematical problems involving angle measure, area, surface area, and volume

Standards basis

Tennessee Academic Standards for Mathematics — Tennessee

How the TCAP reports it

TCAP math is Tennessee’s state assessment program and its blueprints are aligned to Tennessee Academic Standards, which closely mirror the Common Core content structure in grades 3-8 and the CCSS-style high school conceptual categories. The blueprint page lists the current 2025-26 assessment overviews, including Math Grade 2, Grades 3-5, Grades 6-8, and Math EOC. [Tennessee Department of Education](https://www.tn.gov/education/districts/lea-operations/assessment/tcap-blueprints.html)

Blueprint & weighting

Published TCAP math blueprints assign content emphasis by grade/course, but the exact percentage table was not recoverable from the accessible blueprint page in this session. The state blueprint landing page confirms the math overviews but did not expose the PDF links in the fetched page content. [Tennessee Department of Education](https://www.tn.gov/education/districts/lea-operations/assessment/tcap-blueprints.html)

Try it now

8 free questions · 0/0 correct

Practice playeasy

Find the volume of a sphere with radius 33. Use π=3\pi = 3.

V=43πr3=43×3×27=108V = \dfrac{4}{3} \pi r^{3} = \dfrac{4}{3} \times 3 \times 27 = 108.

Practice playeasy

Two angles are complementary. One measures 60°60°. What is the other?

9060=30°90 - 60 = 30°.

Practice playeasy

A circle has a radius of 1111 centimeters. What is the circumference, in centimeters, of the circle?

The circumference of a circle is C=2πrC = 2\pi r. Substitute r=11r = 11: C=2π(11)=22π.C = 2\pi(11) = 22\pi\textsf{.}

Practice playeasy

A circle has radius 11. Using π=3\pi = 3, what is its circumference?

C=2πr=2×3×1=6C = 2\pi r = 2 \times 3 \times 1 = 6.

Practice playeasy

Similar triangles GHIGHI and JKLJKL have perimeters 1616 and 48.48\textsf{.} Side GHGH corresponds to side JK,JK\textsf{,} and GH=5.GH = 5\textsf{.} What is the length of JK?JK\textsf{?}

The scale factor from GHI\triangle GHI to JKL\triangle JKL is 4816=3.\dfrac{48}{16} = 3\textsf{.} Corresponding sides scale by 3,3\textsf{,} so JK=53=15.JK = 5 \cdot 3 = 15\textsf{.}

Practice playhard

A rectangular prism has volume 7272 cubic centimeters and height 44 centimeters. The length is twice the width. What is the width, in centimeters?

V=whV = \ell w h and =2w\ell = 2w, so 72=(2w)(w)(4)=8w272 = (2w)(w)(4) = 8w^2. Then w2=9w^2 = 9 and w=3 cm.w = 3\text{ cm}\textsf{.}

Practice playmedium

A factory seals soup in closed cylindrical cans with radius 33 centimeters and height 55 centimeters. What is the total exterior surface area, in square centimeters, of one closed can?

A closed cylinder has two circular bases and a lateral surface: SA=2πr2+2πrhSA = 2\pi r^2 + 2\pi rh. With r=3r = 3 and h=5h = 5, SA=2π(9)+2π(3)(5)=18π+30π=48πSA = 2\pi(9) + 2\pi(3)(5) = 18\pi + 30\pi = 48\pi square centimeters.

Practice playmedium

Two sides of a triangle measure 1616 and 9.9\textsf{.} Which inequality gives the possible lengths, x,x\textsf{,} of the third side?

The triangle inequality requires 169<x<16+9.|16 - 9| < x < 16 + 9\textsf{.} Simplifying gives 7<x<25.7 < x < 25\textsf{.}

Keep practicing

Turn geometry into game time.

The TCAP placement starts with this test's real coverage map and finds the right difficulty.