WVGSA Grade 7 Statistics and Probability. Practice it free.

Use sampling, comparative inference, and probability models to analyze data and chance. This Grade 7 reporting domain maps to 7 practice skills and 8 representative questions from the playable bank.

Grade 77 mapped skills
What the test measures

Statistics and Probability skills

  1. Understand representative and random sampling.

  2. Use random samples to draw inferences about populations.

  3. Compare populations using measures of center and variability.

  4. Assess overlap between distributions.

  5. Understand probability as a number between 0 and 1.

  6. Approximate probability using long-run frequency.

  7. Develop probability models and evaluate them.

  8. Find compound-event probabilities with lists, tables, tree diagrams, and simulations.

Standards basis

West Virginia College- and Career-Readiness Standards for Mathematics (WVBE Policy 2520.2B) — West Virginia

How the WVGSA reports it

West Virginia’s General Summative Assessment is a state assessment aligned to the West Virginia College- and Career-Readiness Standards rather than a separate national assessment framework. The math blueprint follows CCSS-style grade-band domains and clusters, but the standards are the state’s own West Virginia College- and Career-Readiness Standards.

Blueprint & weighting

WVGSA uses the Independent / state-specific framework (by grade domains structure).

Try it now

8 free questions · 0/0 correct

Practice playeasy

For two independent events, the probability of rolling two 6's: P(A)=16P(A)=\tfrac{1}{6}, P(B)=16P(B)=\tfrac{1}{6}. Find P(A and B)P(A \text{ and } B) as a simplified fraction.

Multiply: P(A and B)=16×16=136P(A \text{ and } B) = \tfrac{1}{6} \times \tfrac{1}{6} = \tfrac{1}{36}.

Practice playmedium

A club has 2424 members. Of these members, 99 play soccer. If one member is selected at random, what is the probability that the member plays soccer?

P(soccer)=924=38P(\text{soccer}) = \dfrac{9}{24} = \dfrac{3}{8}.

Practice playeasy

A bag holds 33 red marbles and 55 blue marbles. One marble is drawn at random. What is the probability it is red?

There are 3+5=83 + 5 = 8 marbles in all, and 33 are red, so P(red)=38P(\text{red}) = \dfrac{3}{8}.

Practice playeasy

The whole numbers 11 through 3636 were each written on separate slips of paper. Those 3636 slips were placed in a box. One slip will be randomly drawn from this box. What is the probability that the slip will show a prime number?

Prime numbers from 11 to 3636 are 2,3,5,7,11,13,17,19,23,29,312, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, giving 1111 favorable outcomes: P=1136P = \tfrac{11}{36}.

Practice playeasy

A standard six-sided die is rolled once. What is the probability of rolling a number greater than 44? Give a simplified fraction.

The favorable faces are 55 and 66, so P=26=13P = \dfrac{2}{6} = \dfrac{1}{3}.

Practice playeasy

In a random sample, 12 of 48 shoppers chose vanilla. What percent of all shoppers would you expect to choose vanilla?

1248=14=25%\dfrac{12}{48} = \dfrac{1}{4} = 25\%.

Practice playeasy

The weather report says there is a 35\dfrac{3}{5} chance of no rain on Saturday and an independent 35\dfrac{3}{5} chance of no rain on Sunday. What is the probability that it does not rain on both days?

Multiply the independent probabilities: 35×35=925\dfrac{3}{5} \times \dfrac{3}{5} = \dfrac{9}{25}.

Practice playeasy

Mia can pick from 55 shirts and 22 hats. How many different (shirt, hat) outfits are possible?

By the counting principle: 5×2=105 \times 2 = 10.

Keep practicing

Turn statistics and probability into game time.

The WVGSA placement starts with this test's real coverage map and finds the right difficulty.