WVGSA Grade 7 Geometry. Practice it free.

Use scale drawings, angle relationships, and area/volume formulas to solve geometric problems. This Grade 7 reporting domain maps to 9 practice skills and 8 representative questions from the playable bank.

Grade 79 mapped skills
What the test measures

Geometry skills

  1. Solve problems involving scale drawings.

  2. Construct geometric figures with given conditions.

  3. Describe slices of three-dimensional figures.

  4. Use circle formulas for area and circumference.

  5. Use angle relationships to solve for unknown angles.

  6. Solve area, volume, and surface area problems for composite figures.

Standards basis

West Virginia College- and Career-Readiness Standards for Mathematics (WVBE Policy 2520.2B) — West Virginia

How the WVGSA reports it

West Virginia’s General Summative Assessment is a state assessment aligned to the West Virginia College- and Career-Readiness Standards rather than a separate national assessment framework. The math blueprint follows CCSS-style grade-band domains and clusters, but the standards are the state’s own West Virginia College- and Career-Readiness Standards.

Blueprint & weighting

WVGSA uses the Independent / state-specific framework (by grade domains structure).

Try it now

8 free questions · 0/0 correct

Practice playeasy

A cylinder has radius 11 and height 55. Using π=3\pi = 3, what is its volume?

V=πr2h=3×1×5=15V = \pi r^2 h = 3 \times 1 \times 5 = 15.

Practice playeasy

Two angles are complementary. One measures 60°60°. What is the other?

9060=30°90 - 60 = 30°.

Practice playeasy

A circle has a radius of 1111 centimeters. What is the circumference, in centimeters, of the circle?

The circumference of a circle is C=2πrC = 2\pi r. Substitute r=11r = 11: C=2π(11)=22π.C = 2\pi(11) = 22\pi\textsf{.}

Practice playeasy

A circle has radius 11. Using π=3\pi = 3, what is its circumference?

C=2πr=2×3×1=6C = 2\pi r = 2 \times 3 \times 1 = 6.

Practice playeasy

Similar triangles GHIGHI and JKLJKL have perimeters 1616 and 48.48\textsf{.} Side GHGH corresponds to side JK,JK\textsf{,} and GH=5.GH = 5\textsf{.} What is the length of JK?JK\textsf{?}

The scale factor from GHI\triangle GHI to JKL\triangle JKL is 4816=3.\dfrac{48}{16} = 3\textsf{.} Corresponding sides scale by 3,3\textsf{,} so JK=53=15.JK = 5 \cdot 3 = 15\textsf{.}

Practice playhard

A rectangular prism has volume 7272 cubic centimeters and height 44 centimeters. The length is twice the width. What is the width, in centimeters?

V=whV = \ell w h and =2w\ell = 2w, so 72=(2w)(w)(4)=8w272 = (2w)(w)(4) = 8w^2. Then w2=9w^2 = 9 and w=3 cm.w = 3\text{ cm}\textsf{.}

Practice playmedium

A factory seals soup in closed cylindrical cans with radius 33 centimeters and height 55 centimeters. What is the total exterior surface area, in square centimeters, of one closed can?

A closed cylinder has two circular bases and a lateral surface: SA=2πr2+2πrhSA = 2\pi r^2 + 2\pi rh. With r=3r = 3 and h=5h = 5, SA=2π(9)+2π(3)(5)=18π+30π=48πSA = 2\pi(9) + 2\pi(3)(5) = 18\pi + 30\pi = 48\pi square centimeters.

Practice playeasy

Find the volume of a sphere with radius 33. Use π=3\pi = 3.

V=43πr3=43×3×27=108V = \dfrac{4}{3} \pi r^{3} = \dfrac{4}{3} \times 3 \times 27 = 108.

Keep practicing

Turn geometry into game time.

The WVGSA placement starts with this test's real coverage map and finds the right difficulty.