NJSLA Algebra I Geometric Measurement and Dimension. Practice it free.

Explain volume formulas and use them to solve problems. This Algebra I reporting domain maps to 2 practice skills and 8 representative questions from the playable bank.

Algebra IG-GMD2 mapped skills
What the test measures

Geometric Measurement and Dimension skills

  1. G-GMD.A.1 Give an informal argument for the formulas for the circumference of a circle, area of a circle, volume of a cylinder, pyramid, and cone

  2. G-GMD.A.2 Give an informal argument using Cavalieri's principle for the formulas for the volume of a sphere and other solid figures

  3. G-GMD.A.3 Use volume formulas for cylinders, pyramids, cones, and spheres to solve problems

Standards basis

New Jersey Student Learning Standards for Mathematics (NJSLS-M), aligned to Common Core State Standards for Mathematics (CCSS-M) — New Jersey

How the NJSLA reports it

NJSLA math is built on the New Jersey Student Learning Standards for Mathematics, which closely follow the Common Core domain structure and progressions. The assessment is organized by grade-level and end-of-course reporting aligned to those standards rather than by a separate proprietary framework.

Blueprint & weighting

NJDOE publishes statewide assessment administration information and grade/course coverage, but no official public math-domain weighting blueprint was located in the retrieved primary materials.

Try it now

8 free questions · 0/0 correct

Practice playeasy

Find the volume of a cylinder with radius 11 and height 1010. Use π=3\pi = 3.

V=πr2h=3×1×10=30V = \pi r^2 h = 3 \times 1 \times 10 = 30.

Practice playmedium

An ice machine makes spherical ice balls with a diameter of 66 centimeters. What is the volume of one ice ball, in cubic centimeters?

The radius is half the diameter: r=3r = 3 cm. Then V=43πr3=43π(3)3=36πV = \dfrac{4}{3}\pi r^{3} = \dfrac{4}{3}\pi (3)^{3} = 36\pi cubic centimeters.

Practice playeasy

Find the volume of a sphere with radius 33. Use π=3\pi = 3.

V=43πr3=43×3×27=108V = \dfrac{4}{3} \pi r^{3} = \dfrac{4}{3} \times 3 \times 27 = 108.

Practice playmedium

A traffic cone is shaped like a right circular cone with a base diameter of 1010 inches and a height of 1212 inches. What is the volume of the cone, in cubic inches?

The radius is 55 inches. V=13πr2h=13π(5)2(12)=100πV = \dfrac{1}{3}\pi r^{2} h = \dfrac{1}{3}\pi (5)^{2}(12) = 100\pi cubic inches.

Practice playeasy

Find the volume of a cone with radius 33 and height 55. Use π=3\pi = 3.

V=13πr2h=13×3×9×5=45V = \dfrac{1}{3}\pi r^2 h = \dfrac{1}{3} \times 3 \times 9 \times 5 = 45.

Practice playmedium

A cylindrical rain barrel has an inside radius of 33 feet. After a storm, the water level rises 44 inches. What is the volume of the added water, in cubic feet?

Convert 44 inches to 13\dfrac{1}{3} foot. V=πr2h=π(3)2(13)=3πV = \pi r^{2} h = \pi (3)^{2}\left(\dfrac{1}{3}\right) = 3\pi cubic feet.

Practice playeasy

Find the volume of a cylinder with radius 33 and height 22. Use π=3\pi = 3.

V=πr2h=3×9×2=54V = \pi r^{2} h = 3 \times 9 \times 2 = 54.

Practice playhard

A concrete drainage pipe is a hollow right circular cylinder. The outer radius is r1=6r_1 = 6 meters, the inner radius is r2=4r_2 = 4 meters, and the pipe is 55 meters long. What is the volume of concrete in the pipe wall, in cubic meters?

Wall volume is outer minus inner: V=πh(r12r22)=π(5)(6242)=π(5)(20)=100πV = \pi h(r_1^{2} - r_2^{2}) = \pi (5)(6^{2} - 4^{2}) = \pi (5)(20) = 100\pi cubic meters.

Keep practicing

Turn geometric measurement and dimension into game time.

The NJSLA placement starts with this test's real coverage map and finds the right difficulty.