NJSLA Algebra II Interpreting Functions. Practice it free.

Understand the concept of a function and use function notation; interpret functions that arise in applications in terms of the context; analyze functions using different representations. This Algebra II reporting domain maps to 11 practice skills and 8 representative questions from the playable bank.

Algebra IIF-IF11 mapped skills
What the test measures

Interpreting Functions skills

  1. F.IF.A.1-3 Function concept and notation

  2. F.IF.B.4-5 Domain and range/average rate of change

  3. F.IF.C.6-9 Graphing and comparing functions

Standards basis

New Jersey Student Learning Standards for Mathematics (NJSLS-M), aligned to Common Core State Standards for Mathematics (CCSS-M) — New Jersey

How the NJSLA reports it

NJSLA math is built on the New Jersey Student Learning Standards for Mathematics, which closely follow the Common Core domain structure and progressions. The assessment is organized by grade-level and end-of-course reporting aligned to those standards rather than by a separate proprietary framework.

Blueprint & weighting

NJDOE publishes statewide assessment administration information and grade/course coverage, but no official public math-domain weighting blueprint was located in the retrieved primary materials.

Try it now

8 free questions · 0/0 correct

Practice playeasy

The xx-intercept of the graph of y=5x15y = 5x - 15 in the coordinate plane is (x,0)(x, 0). What is the value of xx?

At the xx-intercept, y=0y = 0, so 0=5x150 = 5x - 15, 5x=155x = 15, and x=3.x = 3\textsf{.}

Practice playeasy

The function ff is defined by f(x)=7x4f(x) = 7x - 4. What is the value of f(x)f(x) when x=3x = 3?

Substitute x=3x = 3: f(3)=7(3)4=214=17f(3) = 7(3) - 4 = 21 - 4 = 17.

Practice playeasy

The function ff is defined by f(x)=2x+1f(x) = \sqrt{2x + 1}. What is the value of f(x)f(x) when x=4x = 4?

Substitute x=4x = 4: f(4)=2(4)+1=9=3f(4) = \sqrt{2(4) + 1} = \sqrt{9} = 3.

Practice playeasy

For the function pp, p(0)=200p(0) = 200. For each increase in xx by 11, the value of p(x)p(x) decreases by 10%10\%. What is the value of p(2)p(2)?

Each step multiplies by 0.900.90. So p(2)=2000.902=2000.81=162p(2) = 200 \cdot 0.90^2 = 200 \cdot 0.81 = 162.

Practice playeasy

g=9m4g = 9 - \dfrac{m}{4}

The equation shown gives the estimated amount of paint
g,g\textsf{,} in gallons, remaining after covering mm square meters of wall, where 0m36.0 \le m \le 36\textsf{.} What is the estimated amount of paint, in gallons, remaining after covering 1212 square meters of wall?

Substitute m=12:m = 12\textsf{:} g=9124=93=6.g = 9 - \dfrac{12}{4} = 9 - 3 = 6\textsf{.} The estimated amount remaining is 66 gallons.

Practice playmedium

At what xx-value does the graph of y=3(x5)2(x+8)y = 3(x - 5)^2(x + 8) intercept the xx-axis?

Set y=0y = 0: 3(x5)2(x+8)=03(x - 5)^2(x + 8) = 0. The constant 303 \neq 0, so the zeros are x=5x = 5 (from the repeated factor) and x=8x = -8. Among the choices, only 55 is an x-coordinate of an x-intercept.

Practice playmedium

The function hh is defined by h(t)=16t2+64t+5h(t) = -16t^{2} + 64t + 5. The function models the height, in feet, of a baseball tt seconds after it is hit. Which of the following is the best interpretation of the statement "h(2)h(2) is equal to 6969" in this context?

In this model, tt is seconds after the ball is hit and h(t)h(t) is height in feet. So h(2)=69h(2) = 69 means that 22 seconds after the ball is hit, its height is 6969 feet.

Practice playeasy

A warehouse tracks inventory with I(t)=2t2+6t+85I(t) = -2t^2 + 6t + 85, where I(t)I(t) is the number of units on hand tt weeks after a shipment arrives. According to the model, how many units were on hand when the shipment arrived?

When the shipment arrived, t=0t = 0. So I(0)=2(0)2+6(0)+85=85I(0) = -2(0)^2 + 6(0) + 85 = 85 units.

Keep practicing

Turn interpreting functions into game time.

The NJSLA placement starts with this test's real coverage map and finds the right difficulty.