Slope and point from point-slope form. Game on.

Slope and point from point-slope form is a grade 9 math skill aligned to Common Core standard HSF.IF.B.6. Below are 8 practice questions with answers and step-by-step explanations, drawn from the 70 slope and point from point-slope form problems our math games drill.

CCSS HSF.IF.B.670 questions in the bank
Kickoff

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Warm-upeasy

The equation of a line is y−4=−3(x+3).y - 4 = -3(x + 3)\textsf{.} Which point is used to write this equation?

Point-slope form is y−y1=m(x−x1).y - y_1 = m(x - x_1)\textsf{.} The given point is (x1,y1)=(−3,4).(x_1, y_1) = (-3, 4)\textsf{.}

Mid-gameeasy

The equation of a line is y+7=2(x+4).y + 7 = 2(x + 4)\textsf{.} What is the slope of the line?

Point-slope form is y−y1=m(x−x1).y - y_1 = m(x - x_1)\textsf{.} The slope is the coefficient of (x−x1),(x - x_1)\textsf{,} so m=2.m = 2\textsf{.}

Mid-gameeasy

The equation of a line is y+2=23(x+7).y + 2 = \dfrac{2}{3}(x + 7)\textsf{.} Which point is used to write this equation?

Point-slope form is y−y1=m(x−x1).y - y_1 = m(x - x_1)\textsf{.} The given point is (x1,y1)=(−7,−2).(x_1, y_1) = (-7, -2)\textsf{.}

Mid-gameeasy

The equation of a line is y+5=52(x+3).y + 5 = \dfrac{5}{2}(x + 3)\textsf{.} What is the slope of the line?

Point-slope form is y−y1=m(x−x1).y - y_1 = m(x - x_1)\textsf{.} The slope is the coefficient of (x−x1),(x - x_1)\textsf{,} so m=52.m = \dfrac{5}{2}\textsf{.}

Mid-gameeasy

The equation of a line is y+8=23(x+6).y + 8 = \dfrac{2}{3}(x + 6)\textsf{.} Which point is used to write this equation?

Point-slope form is y−y1=m(x−x1).y - y_1 = m(x - x_1)\textsf{.} The given point is (x1,y1)=(−6,−8).(x_1, y_1) = (-6, -8)\textsf{.}

Mid-gameeasy

The equation of a line is y−2=5(x+7).y - 2 = 5(x + 7)\textsf{.} What is the slope of the line?

Point-slope form is y−y1=m(x−x1).y - y_1 = m(x - x_1)\textsf{.} The slope is the coefficient of (x−x1),(x - x_1)\textsf{,} so m=5.m = 5\textsf{.}

Mid-gameeasy

The equation of a line is y−4=2(x+3).y - 4 = 2(x + 3)\textsf{.} Which point is used to write this equation?

Point-slope form is y−y1=m(x−x1).y - y_1 = m(x - x_1)\textsf{.} The given point is (x1,y1)=(−3,4).(x_1, y_1) = (-3, 4)\textsf{.}

Buzzer beatereasy

The equation of a line is y+1=−12(x+5).y + 1 = -\dfrac{1}{2}(x + 5)\textsf{.} What is the slope of the line?

Point-slope form is y−y1=m(x−x1).y - y_1 = m(x - x_1)\textsf{.} The slope is the coefficient of (x−x1),(x - x_1)\textsf{,} so m=−12.m = -\dfrac{1}{2}\textsf{.}

Overtime

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