ILEARN Grade 8 The Number System. Practice it free.

Works with irrational numbers and the properties of integer exponents. This Grade 8 reporting domain maps to 6 practice skills and 8 representative questions from the playable bank.

Grade 86 mapped skills
What the test measures

The Number System skills

  1. Know that there are numbers that are not rational, and approximate them by rational numbers

  2. Use square root and cube root symbols to represent solutions to equations of the form x² = p and x³ = p

  3. Use rational approximations of irrational numbers to compare the size of irrational numbers

  4. Apply properties of integer exponents to generate equivalent numerical expressions

  5. Use scientific notation to estimate very large or very small quantities

Standards basis

Indiana Academic Standards for Mathematics — Indiana

How the ILEARN reports it

Indiana iLEARN is a state assessment system aligned to Indiana’s Academic Standards rather than a shared national testing framework. The public iLEARN page says the math assessment is a computer-adaptive test measuring Indiana mathematics standards, and the through-year summative measures the full set of skills expected by year end ([Indiana DOE iLEARN](https://www.in.gov/doe/students/assessment/ilearn/)).

Blueprint & weighting

The iLEARN public page states that each Checkpoint measures a subset of skills and the summative measures the full set of skills by the end of the school year, but the official page and accessible sources retrieved here do not publish per-domain item percentages or weightings for math ([Indiana DOE iLEARN](https://www.in.gov/doe/students/assessment/ilearn/), [Indiana DOE Formative (Interim) Assessment Grant Guidance](https://www.in.gov/doe/files/2026-2027-Formative-Interim-Assessment-Grant-Guidance.pdf)).

Try it now

8 free questions · 0/0 correct

Practice playeasy

(3⋅7)4=3a⋅7a.(3 \cdot 7)^{4} = 3^{a} \cdot 7^{a}\textsf{.} What is a?a\textsf{?}

The Power of a Product Property says that a product raised to a power equals each factor raised to that power, written (ab)n=an⋅bn.(ab)^{n} = a^{n} \cdot b^{n}\textsf{.} Here (3⋅7)4=34⋅74(3 \cdot 7)^{4} = 3^{4} \cdot 7^{4}, so a=4.a = 4\textsf{.}

Practice playhard

Let f(t)=2e3t+1,000f(t) = 2e^{3t} + 1{,}000. Which of the following approximations, written as a×10na \times 10^n with one significant digit, is closest to the value of f(4)f(4)?

Substitute t=4t = 4: f(4)=2e12+1,000f(4) = 2e^{12} + 1{,}000. Since e12≈162,755e^{12} \approx 162{,}755, f(4)≈2(162,755)+1,000=326,510≈3×105f(4) \approx 2(162{,}755) + 1{,}000 = 326{,}510 \approx 3 \times 10^{5}.

Practice playeasy

(3×102)(3×103)=9×10n(3 \times 10^2)(3 \times 10^3) = 9 \times 10^n. What is nn?

Coefficients multiply to 99; exponents add: 2+3=52 + 3 = 5, so n=5n = 5.

Practice playeasy

Solve for all values of x.x\textsf{.}

x2=81x^{2} = 81

9×9=819 \times 9 = 81 and (−9)×(−9)=81,(-9) \times (-9) = 81\textsf{,} so x=±9.x = \pm 9\textsf{.}

Practice playeasy

If x2=169x^2 = 169 and x>0x > 0, what is xx?

Take the positive square root: x=169=13x = \sqrt{169} = 13 because 13×13=16913 \times 13 = 169.

Practice playeasy

27\sqrt{27} lies between two consecutive integers. Enter the larger one.

52=25<27<36=625^2 = 25 < 27 < 36 = 6^2, so 27\sqrt{27} is between 55 and 66; the larger is 66.

Practice playeasy

Simplify: (y5)2(y^{5})^{2}.

The Power of a Power Property says that a power raised to another power is simplified by multiplying the exponents, written (ym)n=ym⋅n.(y^{m})^{n} = y^{m \cdot n}\textsf{.} Here y5y^{5} is raised to the second power, so (y5)2=y5⋅2=y10.(y^{5})^{2} = y^{5 \cdot 2} = y^{10}\textsf{.}

Practice playhard

Let f(t)=e3tf(t) = e^{3t}. Which of the following approximations, written as a×10na \times 10^n with one significant digit, is closest to the value of f(5)f(5)?

Substitute t=5t = 5: f(5)=e15f(5) = e^{15}. Since e15≈3,269,017e^{15} \approx 3{,}269{,}017, f(5)≈3×106f(5) \approx 3 \times 10^{6}.

Keep practicing

Turn the number system into game time.

The ILEARN placement starts with this test's real coverage map and finds the right difficulty.