NJSLA Grade 7 Geometry Practice — Sports Academy Games

What the test measures

Geometry skills

7.G.A.1 Solve problems involving scale drawings of geometric figures, including computing actual lengths and areas from scale drawings
7.G.A.2 Draw geometric shapes with given conditions
7.G.A.3 Describe the two-dimensional figures that result from slicing three-dimensional figures
7.G.B.4 Know the formulas for area and circumference of a circle and use them to solve problems
7.G.B.5 Use facts about supplementary, complementary, vertical, and adjacent angles in a multi-step problem
7.G.B.6 Solve real-world and mathematical problems involving area, volume, and surface area of two- and three-dimensional objects

Standards basis

New Jersey Student Learning Standards for Mathematics (NJSLS-M), aligned to Common Core State Standards for Mathematics (CCSS-M) — New Jersey

How the NJSLA reports it

NJSLA math is built on the New Jersey Student Learning Standards for Mathematics, which closely follow the Common Core domain structure and progressions. The assessment is organized by grade-level and end-of-course reporting aligned to those standards rather than by a separate proprietary framework.

Blueprint & weighting

NJDOE publishes statewide assessment administration information and grade/course coverage, but no official public math-domain weighting blueprint was located in the retrieved primary materials.

Official sources

New Jersey Department of Education - Assessment
New Jersey Department of Education - 2023 NJSLS-Mathematics
NJDOE - Statewide Assessment Testing Schedule 2026-27

Practice by skill

Topics mapped to this domain

Try it now

8 free questions · 0/0 correct

Practice playeasy

Find the volume of a cone with radius $2$ and height $9$ . Use $\pi = 3$ .

$V = \dfrac{1}{3}\pi r^2 h = \dfrac{1}{3} \times 3 \times 4 \times 9 = 36$ .

Practice playeasy

A cylinder has radius $2$ and height $4$ . Using $\pi = 3$ , what is its volume?

$V = \pi r^2 h = 3 \times 4 \times 4 = 48$ .

Practice playeasy

Two angles are supplementary. One measures $15°$ . What is the other?

$180 - 15 = 165°$ .

Practice playeasy

A circle has a radius of $15$ feet. What is the area, in square feet, of the circle?

The area of a circle is $A = \pi r^{2}$ . Substitute $r = 15$ : $A = \pi(15)^{2} = 225\pi\textsf{.}$

Practice playeasy

A circle has diameter $8$ . Using $\pi = 3$ , what is its circumference?

$C = \pi d = 3 \times 8 = 24$ .

Practice playeasy

Parallelograms $EFGH$ and $JKLM$ are similar. The area of parallelogram $EFGH$ is $9\textsf{,}$ and the area of parallelogram $JKLM$ is $36\textsf{.}$ Side $EF$ corresponds to side $JK\textsf{,}$ and $EF = 7\textsf{.}$ What is the length of $JK\textsf{?}$

The area ratio is $\dfrac{36}{9} = 4 = k^{2}\textsf{,}$ so $k = 2\textsf{.}$ Then $JK = 7 \cdot 2 = 14\textsf{.}$

Practice playhard

A rectangular prism has volume $72$ cubic centimeters and height $4$ centimeters. The length is twice the width. What is the width, in centimeters?

$V = \ell w h$ and $\ell = 2w$ , so $72 = (2w)(w)(4) = 8w^2$ . Then $w^2 = 9$ and $w = 3\text{ cm}\textsf{.}$

Practice playhard

A rectangular pyramid tent has a $10$ -foot-by- $4$ -foot rectangular base. The two triangular faces along the $10$ -foot sides each have slant height $6$ feet, and the two triangular faces along the $4$ -foot sides each have slant height $5$ feet. The tent has no floor. What is the exterior surface area, in square feet, of the tent fabric?

Without a floor, only the four triangular faces are counted. Along the $10$ -foot sides: $2 \times \dfrac{1}{2}(10)(6) = 60$ . Along the $4$ -foot sides: $2 \times \dfrac{1}{2}(4)(5) = 20$ . The total is $60 + 20 = 80$ square feet.