OSTP Grades 6-8 Geometry. Practice it free.

The tent holds $V = \dfrac{1}{3}Bh = \dfrac{1}{3}(6)^{2}(4) = 48$ cubic feet. Then $48 \div 16 = 3$ campers.

$180 - 15 = 165°$.

The circumference of a circle is $C = \pi d$. Substitute $d = 26$: $C = \pi(26) = 26\pi\textsf{.}$

Triangle area $= \dfrac{1}{2} \cdot b \cdot h = \dfrac{1}{2} \cdot 8 \cdot 9 = 36$.

The area of a rhombus is half the product of the diagonals: $\dfrac{1}{2} \cdot 11 \cdot 8 = 44\text{ m}^{2}\textsf{.}$

$A = \pi r^2 = 3 \times 4 = 12$.

$\sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13$.

The two congruent angles total $2 \times 61.7^{\circ} = 123.4^{\circ}$, so $\angle K = 180^{\circ} - 123.4^{\circ} = 56.6^{\circ}$.