PARCC Algebra I Statistics and Probability. Practice it free.

Students make inferences and justify conclusions from sample surveys, experiments, and observational studies. This Algebra I reporting domain maps to 9 practice skills and 8 representative questions from the playable bank.

Algebra I9 mapped skills
What the test measures

Statistics and Probability skills

  1. Summarize, represent, and interpret data on a single count or measurement variable

  2. Make inferences and justify conclusions from sample surveys, experiments, and observational studies

  3. Calculate expected values and use them to solve problems

Standards basis

Common Core State Standards for Mathematics (CCSS-M) / PARCC Model Content Frameworks — national

How the PARCC reports it

PARCC was a multistate assessment system built around the Common Core-era PARCC mathematics model content frameworks rather than a separate proprietary standards set. Its math structure is organized by grade/course and aligned to CCSS-M content categories and model content frameworks.

Blueprint & weighting

No single published PARCC weighting table was located in the accessible sources used here.

Try it now

8 free questions · 0/0 correct

Practice playeasy

A survey recorded the number of text messages sent per day. Which group has the greatest standard deviation?

Group A:
50,50,50,50,5050, 50, 50, 50, 50
Group B:
40,45,50,55,6040, 45, 50, 55, 60
Group C:
48,49,50,51,5248, 49, 50, 51, 52
Group D:
30,50,50,50,7030, 50, 50, 50, 70

Group D has mean 5050 with values 3030 and 7070 each 2020 away from the center while three values sit at the mean, giving a standard deviation of about 12.612.6. Groups B and C spread less; Group A has zero spread.

Practice playeasy

The practice times, in minutes, for five days are 18,18\textsf{,} 22,22\textsf{,} 30,30\textsf{,} 20,20\textsf{,} and 35.35\textsf{.} Which data set has the same mean?

The original mean is 18+22+30+20+355=25\dfrac{18 + 22 + 30 + 20 + 35}{5} = 25. The set 15,15\textsf{,} 20,20\textsf{,} 25,25\textsf{,} 30,30\textsf{,} 3535 also has mean 2525, so the means match.

Practice playeasy

Five quiz scores are 92,92\textsf{,} 68,68\textsf{,} 75,75\textsf{,} 88,88\textsf{,} and 77.77\textsf{.} Which data set has the same median?

In order, the original values have middle value 7777, so the median is 7777. The set 70,70\textsf{,} 73,73\textsf{,} 77,77\textsf{,} 91,91\textsf{,} 9797 also has median 7777, so the medians match.

Practice playeasy

A lemonade stand earns $15\text{\char36}15 on a busy day, $5\text{\char36}5 on a slow day, or $0\text{\char36}0 if it rains. A busy day is equally likely as a slow day, and a rainy day is twice as likely as a slow day. What is the expected profit?

Weights are 11, 11, and 22 (total 44), so probabilities are 14\dfrac{1}{4}, 14\dfrac{1}{4}, and 24\dfrac{2}{4}. Then E=piviE = \sum p_i v_i, which means the sum of each probability times its value: E=14(15)+14(5)+24(0)=$5E = \dfrac{1}{4}(15) + \dfrac{1}{4}(5) + \dfrac{2}{4}(0) = \text{\char36}5.

Practice playeasy

During a fitness challenge, four teammates completed 1515, 2020, 1818, and 2222 push-ups in the first four rounds. In the fifth round, one teammate completed xx push-ups. The mean number of push-ups per round is 1919. What is the value of xx?

Five rounds with a mean of 1919 push-ups total 5×19=955 \times 19 = 95. Since 15+20+18+22=7515 + 20 + 18 + 22 = 75, x=9575=20x = 95 - 75 = 20.

Practice playeasy

A box plot summarizes the data 1, 3, 3, 5, 8, 8, 10, 12. Find the median.

Order the data; the middle value is 6.56.5.

Practice playeasy

Quiz scores are approximately normally distributed with mean 8080 and standard deviation 44. By the empirical rule, about what percent of scores are between 7272 and 8888? (Enter the number of percent.)

7272 and 8888 are each 2×4=82 \times 4 = 8 points, or 2 standard deviations, from the mean 8080, so by the empirical rule about 95%95\% of scores fall between them.

Practice playmedium

A grocer surveyed 2525 customers selected at random and found that 1515 of them purchased at least one organic item. Based on the survey, which of the following is the best estimate of the number of customers out of 500500 who would purchase at least one organic item?

The sample proportion is 1525=35\dfrac{15}{25} = \dfrac{3}{5}. The best estimate for 500500 customers is 35×500=300\dfrac{3}{5} \times 500 = 300 customers.

Keep practicing

Turn statistics and probability into game time.

The PARCC placement starts with this test's real coverage map and finds the right difficulty.