PARCC Grades 6-8 Geometry. Practice it free.

Students solve real-world and mathematical problems involving angle, area, surface area, and volume and work with congruence and similarity. This Grades 6-8 reporting domain maps to 13 practice skills and 8 representative questions from the playable bank.

Grades 6-813 mapped skills
What the test measures

Geometry skills

  1. Draw, construct, and describe geometrical figures and describe the relationships between them

  2. Solve real-world and mathematical problems involving area, surface area, and volume

  3. Understand congruence and similarity using physical models, transparencies, or geometry software

  4. Solve real-world and mathematical problems involving volume of cylinders, cones, and spheres

Standards basis

Common Core State Standards for Mathematics (CCSS-M) / PARCC Model Content Frameworks — national

How the PARCC reports it

PARCC was a multistate assessment system built around the Common Core-era PARCC mathematics model content frameworks rather than a separate proprietary standards set. Its math structure is organized by grade/course and aligned to CCSS-M content categories and model content frameworks.

Blueprint & weighting

No single published PARCC weighting table was located in the accessible sources used here.

Try it now

8 free questions · 0/0 correct

Practice playeasy

Find the volume of a cylinder with radius 33 and height 22. Use π=3\pi = 3.

V=πr2h=3×9×2=54V = \pi r^{2} h = 3 \times 9 \times 2 = 54.

Practice playeasy

A cylinder has radius 22 and height 33. Using π=3\pi = 3, what is its volume?

V=πr2h=3×4×3=36V = \pi r^2 h = 3 \times 4 \times 3 = 36.

Practice playeasy

Two lines cross. One angle formed is 75°75°. What is the vertical angle?

Vertical angles are equal, so the angle is 75°75°.

Practice playeasy

A circle has a diameter of 1616 inches. What is the area, in square inches, of the circle?

The radius is half the diameter: r=162=8r = \dfrac{16}{2} = 8. The area is A=πr2=π(8)2=64π.A = \pi r^{2} = \pi(8)^{2} = 64\pi\textsf{.}

Practice playeasy

Find the area of a parallelogram with base b=2b = 2 and height h=9h = 9.

Parallelogram area =bh=29=18= b \cdot h = 2 \cdot 9 = 18.

Practice playeasy

A circle has radius 22. Using π=3\pi = 3, what is its circumference?

C=2πr=2×3×2=12C = 2\pi r = 2 \times 3 \times 2 = 12.

Practice playeasy

Similar triangles RSTRST and UVWUVW have perimeters 2828 and 42.42\textsf{.} Side RSRS corresponds to side UV,UV\textsf{,} and RS=10.RS = 10\textsf{.} What is the length of UV?UV\textsf{?}

The scale factor from RST\triangle RST to UVW\triangle UVW is 4228=32.\dfrac{42}{28} = \dfrac{3}{2}\textsf{.} So UV=1032=15.UV = 10 \cdot \dfrac{3}{2} = 15\textsf{.}

Practice playmedium

In JKL\triangle JKL, J\angle J and L\angle L are congruent. The measure of each of these angles is 61.761.7^{\circ}. What is the measure of K\angle K?

The two congruent angles total 2×61.7=123.42 \times 61.7^{\circ} = 123.4^{\circ}, so K=180123.4=56.6\angle K = 180^{\circ} - 123.4^{\circ} = 56.6^{\circ}.

Keep practicing

Turn geometry into game time.

The PARCC placement starts with this test's real coverage map and finds the right difficulty.