PSAT/NMSQT Geometry and Trigonometry. Practice it free.

Focuses on area and volume, lines, angles, triangles, and trigonometry. This All grades reporting domain maps to 25 practice skills and 8 representative questions from the playable bank.

Grades 10-1125 mapped skills
What the test measures

Geometry and Trigonometry skills

  1. Area and volume

  2. Lines, angles, and triangles

  3. Right triangles and trigonometry

  4. Circles

  5. Graphs of circles and other geometric figures

Standards basis

College Board SAT Suite content domains aligned to college- and career-ready math skills; Common Core State Standards–aligned at the content level — national

How the PSAT/NMSQT reports it

PSAT/NMSQT uses the same SAT Suite digital test design and shared math content domains as SAT and the other PSATs. College Board states these tests assess the same group of skills and knowledge, with content aligned to the SAT Suite’s domain framework rather than a state-specific blueprint.

Blueprint & weighting

College Board’s SAT Suite math content domains are used for reporting and preparation, but the primary sources retrieved here did not provide a PSAT/NMSQT-specific published item percentage by domain in accessible form.

Try it now

8 free questions · 0/0 correct

Practice playeasy

A triangle has sides 55, 1212, and 1313. What is its area?

This is a right triangle (55-1212-1313). Area =12×5×12=30= \dfrac{1}{2} \times 5 \times 12 = 30.

Practice playeasy

Two angles are supplementary. One measures 45°45°. What is the other?

18045=135°180 - 45 = 135°.

Practice playeasy

A circle has a diameter of 2020 feet. What is the circumference, in feet, of the circle?

The circumference of a circle is C=πdC = \pi d. Substitute d=20d = 20: C=π(20)=20π.C = \pi(20) = 20\pi\textsf{.}

Practice playeasy

Find the area of a trapezoid with bases b1=7b_1 = 7 and b2=10b_2 = 10 and height h=6h = 6.

Trapezoid area =12(b1+b2)h=12(7+10)6=12(17)6=51= \dfrac{1}{2}(b_1 + b_2) \cdot h = \dfrac{1}{2}(7 + 10) \cdot 6 = \dfrac{1}{2}(17) \cdot 6 = 51.

Practice playmedium

A circle in the coordinate plane has a diameter with endpoints (0,0)(0, 0) and (6,8).(6, 8)\textsf{.} What is the radius of the circle?

The diameter length is (60)2+(80)2=36+64=100=10.\sqrt{(6 - 0)^2 + (8 - 0)^2} = \sqrt{36 + 64} = \sqrt{100} = 10\textsf{.} The radius is half the diameter, so r=102=5.r = \dfrac{10}{2} = 5\textsf{.}

Practice playeasy

The equation (x2)2+(y+1)2=16(x - 2)^2 + (y + 1)^2 = 16 represents Circle A. Circle B is obtained by shifting Circle A down 33 units in the coordinate plane. Which of the following equations represents Circle B?

Circle A has center (2,1)(2, -1) and radius 44. Shifting down 33 moves the center to (2,4)(2, -4), so Circle B is (x2)2+(y+4)2=16(x - 2)^2 + (y + 4)^2 = 16.

Practice playeasy

A circle has radius 33. Using π=3\pi = 3, what is its area?

A=πr2=3×9=27A = \pi r^2 = 3 \times 9 = 27.

Practice playeasy

How long is the segment joining (1,5)(-1, -5) and (1,2)(-1, 2)?

Both points have x=1x = -1, so the length is 2(5)=7|2 - (-5)| = 7.

Keep practicing

Turn geometry and trigonometry into game time.

The PSAT/NMSQT placement starts with this test's real coverage map and finds the right difficulty.